Question

Graph the line that contains the point (-3,1) with a slope of 2/3

Answer 1

Answer:

The graph of the line $y=\frac{2}{3}x+3$ that contains the point (-3,1) with a slope of 2/3 is attached below.

Step-by-step explanation:

We know that the slop-intercept form of the equation is

$y=mx+b$

where m is the slope, and b is the y-intercept.

Given the slope = m = 2/3, and point (-3, 1)

$1=\frac{2}{3}\left(-3\right)+b$

$-\frac{2}{3}\cdot \:3+b=1$

$-2+b=1$

$b=3$

so the equation of line will be:

$y=mx+b$

$y=\frac{2}{3}x+3$

Also, the graph of the line $y=\frac{2}{3}x+3$ that contains the point (-3,1) with a slope of 2/3 is attached below.