Q3.

Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0

4 years ago

RESPONDE LAS PREGUNTAS 8, 9 Y 10 DE ACUERDO CON LA

andrew-mc [135]

Answer:

ANSWER QUESTIONS 8, 9 AND 10 ACCORDING TO THE

NEXT INFORMATION

Luis painted a mural that

has 760 cm of

perimeter; your measurements are

show in the following

figure.

8. The expression associated with the length of the mural: 2x - 40, is

can interpret as

A. the length is 40 cm less than twice its width

B. the length exceeds the width value by 40 cm

C. the width squared, minus 40 cm, equals the length

D. 40 cm minus twice the width is the value of the length

9. What are the measurements in centimeters of the mural?

A. length: 150, width: 190 B. length: 210, width: 250

B. length: 210, width: 250

C. length: 240, width: 140 D. length: 230, width: 190

D. length: 230, width: 190

10. The area Luis used to paint the mural is

A. 2 [(2x - 40) + x] B. 2x2 - 40x

B. 2x2 - 40x

C. (2x) x - 40 D. x2 - 40x

D. x2 - 40x

Step-by-step explanation:

6 0

3 years ago

Solve Quadratic Equations by Factoring:

mr_godi [17]

Answer:

x = 0 or 1
x = ±i/4
x = -5 (twice)

Step-by-step explanation:

Factoring is aided by having the equations in standard form. The first step in each case is to put the equations in that form. The zero product property tells you that a product is zero when a factor is zero. The solutions are the values of x that make the factors zero.

1. x^2 -x = 0

x(x -1) = 0 . . . . . x = 0 or 1

__

2. 16x^2 +1 = 0

This is the "difference of squares" ...

(4x)^2 - (i)^2 = 0

(4x -i)(4x +i) = 0 . . . . . x = -i/4 or i/4 (zeros are complex)

__

3. x^2 +10x +25 = 0

(x +5)(x +5) = 0 . . . . . x = -5 with multiplicity 2

5 0

3 years ago

There were 120 tickets sold for a band concert and 3/4 of those were student tickets how many adult tickets for the concert were

Deffense [45]

Answer:

30 because if u divided 120 by 4 its 30 and the parents get 1/4 so its 3....... 30/120

3 0

2 years ago

Which group shows 0.25 of the faces smiling?

Ivahew [28]

Answer:

My dude the groul that shows that tiny bit of smiling must be the beatles or backstreet boys

6 0

3 years ago