You found CD from the Pythagorean theorem to be ...
... CD = √(5² -2²) = √21
Since triangle ADC ~ triangle ACB, the ratios of corresponding sides are the same:
... AC/AD = AB/AC
... AB = AC²/AD
... AB = 5²/2 = 12.5 . . . . . . . the base of the overall triangle
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Then the area (A) is ...
... A = (1/2)bh
... A = (1/2)(12.5)(√21) ≈ 28.64 square units
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As you see here, the altitude of a right triangle divides it into three similar triangles. From smallest to largest, they are ...
... ADC ~ CDB ~ ACB
You can figure this using AAA similarity, since the smallest and largest triangles listed above share an acute angle vertex (∠A). That, together with the right angle, means all angles are congruent. After that, then you know ∠ACD ≅ ∠CBD, so you can show the middle sized triangle is similar to the other two.
Answer: v=10
Step-by-step explanation:
since you didn’t put a y on there, I solved for v.
Answer:
it would be A:55%
Step-by-step explanation
For percent, to make it easier try to turn it into a 100.
20x5=100
do the same to the 9.
9x5=45.
Now subtract 45 from 100.
100-45=55.
There was a discount of 55%.
The rationalized form of 1+ √2/1-√2 is -2√2-3
Answer:
- 400 adult tickets
- 325 children's tickets
Step-by-step explanation:
Let x represent the number of adult tickets sold. Then 725-x is the number of children's tickets sold, and the total revenue is ...
2.50x +1.50(725 -x) = 1487.50
1.00x + 1087.50 = 1487.50 . . . . . eliminate parentheses
x = 400 . . . . . . . . . . . . . . . . . . . . . subtract 1087.50
There were 400 adult tickets and 325 children's tickets sold.
