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3 years ago

12

Identify the slope of the line for the equation y =

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

Answer:

1/6

Step-by-step explanation:

The slope is the number in front of the x.

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G(n)=4n+4<br> F(n)= n^3+2n<br> Find (g-f)(n)

masha68 [24]

5525267283838625151627383

6 0

3 years ago

The function h(t) = −16t2 + 24t models the height, in feet, of a kangaroo t seconds after it jumps. What is the maximum height o

ch4aika [34]

<h2>9 ft</h2>

Step-by-step explanation:

The height of kangaroo after it jumps is represented by the function $h(t)=24t-16t^{2}$ , where $t$ is in seconds, height is in feet.

To find the maximum height that the kangaroo jumps, we need to maximise $h(t)$ .

The minimum/maximum value of a quadratic expression $ax^{2}+bx+c$ is given by $\dfrac{4ac-b^{2}}{4a}$ .

As the coeffecient of quadratic term is negative, the function has a maxima.

Maximum value = $\dfrac{4(-16)(0)-(24)^{2}}{4(-16)}=\dfrac{-576}{-64}=9$ .

∴ Maximum height = 9 ft

6 0

3 years ago

What’s the correct answer for this question?

Ilya [14]

Answer:

C.

Step-by-step explanation:

Volume of cylinder = πr²h

= (3.14)(4)(0.75)

= 9.4

Since she'll fill it half so

Amount of water to be filled = 4.7

8 0

3 years ago

5. A tree is broken at a height of 5 m from the ground

tensa zangetsu [6.8K]

The original height of the tree is 60 m

8 0

3 years ago

Read 2 more answers

The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth

Bess [88]

Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

$\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE$ are equilateral $\triangle s$ .

Area of an equilateral $\triangle$ is defined as :

$\dfrac{\sqrt{3}}{4} \times a^{2}$

Where <em>a </em>is the side of $\triangle$ .

Area of hexagon = $6 \times \dfrac{\sqrt{3}}{4}\times a^{2}$

We are given that area of hexagon = 169.74 $ft^{2}$

Let <em>s </em>be the side of hexagon.

$\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft$

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = $6 \times side$

Perimeter = $6 \times 8.08$

$\Rightarrow 48.5 ft$

So, perimeter of given regular hexagon is $48.5 ft$ .

6 0

3 years ago