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1 year ago

Please help I'm stuck on this question! worth 15+ points!!

Mathematics

2 answers:

GarryVolchara [31]1 year ago

4 0

Answer:

90°

Step-by-step explanation:

Taking ΔVWX :

∠V = ∠X (equal angles opposing equal side lengths)
Using the Angle Sum Property,
∠V + ∠W + ∠X = 180°
b + 2∠V = 180°
b + 2(45) = 180°
b + 90° = 180°
b = 90°

zvonat [6]1 year ago

3 0

Answer:

152

Step-by-step explanation:

360-(118+54)

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I'm sorry hun, i suck at math. If i knew how i would help you. Have you tried looking it up?

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The legs of an isosceles right triangle both measure 10 inches. Find the length of the hypotenuse.

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Answer:

14.14

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2 years ago

18 ÷ 6 × [4 - 3] + 6

shepuryov [24]

Answer:

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2 years ago

Read 2 more answers

Simplify. Consider all cases. |14−(x−6)| |14−(6-x)|

S_A_V [24]

Answer:

8+x if x > -8

8 if x = 0

-8-x if x < -8

Step-by-step explanation:

|14−(6-x)|

|14−6+x|

|8+x|

8+x if x > -8

8 if x = 0

-8-x if x < -8

8 0

3 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

Hence, the theorem that compares both triangles is the SAS theorem

4 0

2 years ago