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3 years ago

15 points

Mathematics

1 answer:

kirza4 [7]3 years ago

4 0

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<h3>ANSWER:</h3>

$\tt\large{y=\frac{9}{2}}$

$\tt\large{x=-5+y}$

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Find the standard form of the equation of the parabola with a focus at (0, -3) and a directrix at y = 3. (5 points)

OLEGan [10]

Answer:

From given option , the equation of parabola is y = negative x² divided by 12

Step-by-step explanation:

Given as for parabola :

The focus is at (0 , - 3)

The directrix equation is y = 3

Now, equation of parabola parallel to y-axis is

( x - h )² = 4 p ( y - k )

where focus is ( h , k+p ) and directrix equation is y = k - p

So, from equation

h = 0 and k + p = - 3

And y = k - p i.e k - p = 3

Now solving ( k + p ) + ( k - p ) = - 3 + 3

or, 2 k = 0 ∴ k = 0

Put the value of k , k + p = - 3

So, 0 + p = - 3 ∴ p = - 3

Now equation of parabola with h = 0 , k = 0 , p = - 3

( x - h )² = 4 p ( y - k )

I.e ( x - 0 )² = 4 × ( - 3 ) ( y - 0 )

Or, x² = - 12 y is the equation of parabola

Hence From given option , the equation of parabola is y = negative x² divided by 12 Answer

7 0

3 years ago

Our product is equal to 6+2 what factors are we

IceJOKER [234]

The factors you would use would be 2 and 4

6 0

3 years ago

Read 2 more answers

From the point on the ground 500 ft from the base of a building, it is observed that the angle of elevation to the top of the bu

AveGali [126]

Answer:

building: 222.61 ft
flagpole: 32.15 ft

Step-by-step explanation:

The tangent function of an angle in a right triangle is the ratio of the opposite side to the adjacent side. Here, the adjacent side is 500 ft, so we have ...

tan(24°) = (building height)/(500 ft)

building height = (500 ft)tan(24°) ≈ 222.61 ft

Similarly, the height to the top of the flagpole is ...

total height = (500 ft)tan(27°) ≈ 254.76 ft

The length of the flagpole is the difference of these heights:

flagpole length = 254.76 ft -222.61 ft = 32.15 ft

The height of the building is 222.61 ft; the length of the flagpole is 32.15 ft.

5 0

3 years ago

P=(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} ) : \frac{4x}{(x-1)^{2} }

balandron [24]

The solution to the division of the given surd is: $\mathbf{P =\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{8x} }$

<h3>Division of Surds.</h3>

The division of surds follows a systemic approach whereby we divide the whole numbers separately and the root(s) are being divided by each other.

Given that:

$\mathbf{P=(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} ) : \frac{4x}{(x-1)^{2} }}$

i.e.

$\mathbf{=\dfrac{(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} )}{ \frac{4x}{(x-1)^{2} }} }$

Using the fraction rule:

$\mathbf{\dfrac{a}{\dfrac{b}{c}}= \dfrac{a\times c}{b}}$

$\mathbf{\implies \dfrac{(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} )(x-1)^{2}}{4x}} }$

By simplification, we have:

$\mathbf{ =\dfrac{\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{2} }{4x} }$

$\mathbf{P =\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{8x} }$

Learn more about evaluating the division of surds here:

https://brainly.in/question/27942899

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6 0

2 years ago

Please help me!!!!!!!!!!

Oksanka [162]

You are allowed to move the decimal points before dividing with decimals because then, you will be able to divide by a whole number outside the dividend. Move the decimal point so that you are dividing by a whole number.

5 0

3 years ago