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Vinvika [58]
3 years ago
13

HELP ME OUT PLS ILL GIVE BRAINLIEST

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0

Answer:

C. 3 {x}^{5}  - 4 {x}^{4}  -  {x}^{2}  - 5x + 5[ /tex] Step-by-step explanation:[tex](3x^5-2x^4-5x-5)\\-(2x^4+x^2-10)

= 3x^5-2x^4-5x-5\\-2x^4  +  x^2 + 10

= 3 {x}^{5}  - 4 {x}^{4}  -  {x}^{2}  - 5x + 5

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Solve the equation for the unknown quantity: 15.75=5(1+i)^2
tigry1 [53]
15.75=5(1+i)^2
3.15=1+i^2
2.15=i^2
i= √2.15 or approximately 1.47
7 0
3 years ago
Type the correct answer in each box
Luba_88 [7]

Answer:

We know that the equation of the circle in standard form is equal to <em>(x-h)² + (y-k)² = r²</em> where (h,k) is the center of the circle and r is the radius of the circle.

We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :

1 - We first group terms with the same variable :

(x²+8x) + (y²+22y) + 37 = 0

2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)

(x²+8x) + (y²+22y) = - 37

3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process <u><em>"completing the square"</em></u>.

x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²

y²+22y = (y²+22y+11²)-11² = (y+11)²-11²

4 - We plug the new values inside our equation :

(x+4)² - 4² + (y+22)² - 11² = -37

(x+4)² + (y+22)² = -37+4²+11²

(x+4)²+(y+22)² = 100

5 - We re-write in standard form :

(x-(-4)²)² + (y - (-22))² = 10²

And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)

5 0
3 years ago
Someone please help me
pickupchik [31]
The answer for this question is -3
5 0
3 years ago
Hello, good morning i hope you guys day is going good so far. Can someone help me with finding the area of this trapezoid? Thank
Alexandra [31]

Answer:

210

Step-by-step explanation:

Formula Base+base/2xh

6 0
3 years ago
Read 2 more answers
Triangle ABC has side lengths a= 24, b= 40, and c= 55. What is the measure of angle C? 83.6° 116.2° 23.0° 40.7°
Harlamova29_29 [7]
<h3>Answer:  116.2°</h3>

Work Shown:

c^2 = a^2 + b^2 - 2ab\cos(C)\\\\55^2 = 24^2 + 40^2 - 2*24*40\cos(C)\\\\3025 = 576 + 1600 - 1920\cos(C)\\\\3025 = 2176 - 1920\cos(C)\\\\3025 - 2176  = -1920\cos(C)\\\\849  = -1920\cos(C)\\\\-1920\cos(C) = 849\\\\\cos(C) = (849)/(-1920)\\\\\cos(C) \approx -0.4421875\\\\C \approx \cos^{-1}(-0.4421875)\\\\C \approx 116.243535748231^{\circ}\\\\C \approx 116.2^{\circ}\\\\

The first equation is one of the three variations for the Law of Cosines.

Make sure your calculator is in degree mode.

5 0
2 years ago
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