The correct answer is 24-2D...so you’re answer is D. And I’m also a kpop/Enhypen stan
Answer:
5 times as many should be your answer.
A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is

. We have

so this vector field is not conservative.
- - -
Another way of determining the same result: We want to find a scalar function

such that its gradient is equal to the given vector field,

:

For this to happen, we need to satisfy

From the first equation, integrating with respect to

yields

Note that

*must* be a function of

only.
Now differentiate with respect to

and we have

but this contradicts the assumption that

is independent of

. So, the scalar potential function does not exist, and therefore the vector field is not conservative.
Answer:
(p−3)⋅(3p+2)
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
(3p2 - 7p) - 6
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 3p2-7p-6
The first term is, 3p2 its coefficient is 3 .
The middle term is, -7p its coefficient is -7 .
The last term, "the constant", is -6
Step-1 : Multiply the coefficient of the first term by the constant 3 • -6 = -18
Step-2 : Find two factors of -18 whose sum equals the coefficient of the middle term, which is -7 .
-18 + 1 = -17
-9 +2 = -7 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 2
3p2 - 9p + 2p - 6
Step-4 : Add up the first 2 terms, pulling out like factors :
3p • (p-3)
Add up the last 2 terms, pulling out common factors :
2 • (p-3)
Step-5 : Add up the four terms of step 4 :
(3p+2) • (p-3)
Which is the desired factorization
Final result :
(p - 3) • (3p + 2)