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Otrada [13]
3 years ago
11

Find question attached.​

Mathematics
2 answers:
natali 33 [55]3 years ago
4 0

<u>a) Solution</u>

By using the inscribed angle is half of central angle,

→ 3x = 2 × 75

→ 3x = 150

→ x = 150/3

→ x = 50°

Thus, 50° is the value of x.

<u>b) Solution</u>

By using the exterior angle is equal to sum of two opposite interior angle of triangle,

→ <BDC = 34+x

→ <DCB = 34+x

(base angle of isosceles triangle)

→ <ABC = 90°

(inscribed angle on a semi circle is 90°)

Then in ∆ ABC,

By sum of interior angle of a triangle is 180°,

→ <A+<B+<C = 180°

→ 34+90+34+x=180°

→ x = 180°-90°-68°

→ x = 90°-68°

→ x = 22°

Thus, 22° is the value of x.

Digiron [165]3 years ago
3 0

a.x=50°

b.x=22°

Answer:

Solution given:

a:

3x=2*75°[inscribed angle is half of central angle]

3x=150°

x=150°/3=50°

<u>x</u><u>=</u><u>5</u><u>0</u><u>°</u>

b.

<BDC=34°+x[exterior angle is equal to the sum of two opposite interior angle of triangle]

again

<DCB=34°+x[base angle of isosceles triangle]

again

<ABC=90°[inscribed angle on a semi circle is 90°]

Now.

In triangle

ABC

<A+ <B+<C=180°[sum of interior angle of a triangle is 180°]

34°+90°+34°+x=180°

x=180°-90°-68°

x=90°-68°

x=22°

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