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Oksi-84 [34.3K]

2 years ago

13

Three different design configurations are being considered for a particular component. There are two possible failure modes for

the component. An engineer obtained the following data on the number of failures in each mode for each of the three configurations. Is there evidence to conclude that the configuration has an effect on the type of failure?
Failure Mode
1 2 3 4
Configuration 1 20 44 17 9
2 4 17 7 12
3 10 31 14 5

1 answer:

asambeis [7]2 years ago

3 0

Answer:

No evidence .because the configurations factors and failure mode are independent

Step-by-step explanation:

Determine if there is sufficient evidence to conclude that configuration affects the type of failure

Number of configurations = 3

Number of failures = 4

assuming <em>Pij </em>represents proportion of items in pop i of the category j

H0 : <em>Pij = Pi * </em>Pj<em>, </em>I = 1,2,-- I, j = 1,2,---J

Hence the expected frequencies will be

16.10 , 43.58 , 18, 12.31

7.5, 19.37, 8 , 5.47

10.73, 29.05, 12, 8.21

x^2 = 13.25

test statistic = 14.44. Hence the significance level where Null hypothesis will be acceptable will be = 2.5%

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3 years ago

Read 2 more answers

Determine the first five iterates of f(x)=1.5x(1-x) for x0=0.8

kherson [118]

<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
f(0.24) = 1.5(0.24)(1 - 0.24) ~= 0.274
f(0.274) = 1.5(0.274)(1 - 0.274) ~= 0.298
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3 0

2 years ago

Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.

Leni [432]

Answer:

a)

$g(2.9) \approx -6.6$

$g(3.1) \approx -3.4$

b)

The values are too small since $g''$ is positive for both values of $x$ in. I'm speaking of the $x$ values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on that line.

We want to find the equation of the tangent line of the curve $g$ at the point $(3,-5)$ on $g$ .

So we know $(x_1,y_1)=(3,-5)$ .

To find $m$ , we must calculate the derivative of $g$ at $x=3$ :

$m=g'(3)=(3)^2+7=9+7=16$ .

So the equation of the tangent line to curve $g$ at $(3,-5)$ is:

$y-(-5)=16(x-3)$ .

I'm going to solve this for $y$ .

$y-(-5)=16(x-3)$

$y+5=16(x-3)$

Subtract 5 on both sides:

$y=16(x-3)-5$

What this means is for values $x$ near $x=3$ is that:

$g(x) \approx 16(x-3)-5$ .

Let's evaluate this approximation function for $g(2.9)$ .

$g(2.9) \approx 16(2.9-3)-5$

$g(2.9) \approx 16(-.1)-5$

$g(2.9) \approx -1.6-5$

$g(2.9) \approx -6.6$

Let's evaluate this approximation function for $g(3.1)$ .

$g(3.1) \approx 16(3.1-3)-5$

$g(3.1) \approx 16(.1)-5$

$g(3.1) \approx 1.6-5$

$g(3.1) \approx -3.4$

b) To determine if these are over approximations or under approximations I will require the second derivative.

If $g''$ is positive, then it leads to underestimation (since the curve is concave up at that number).

If $g''$ is negative, then it leads to overestimation (since the curve is concave down at that number).

$g'(x)=x^2+7$

$g''(x)=2x+0$

$g''(x)=2x$

$2x$ is positive for $x>0$ .

$2x$ is negative for $x$ .

That is, $g''(2.9)>0 \text{ and } g''(3.1)>0$ .

So $2x$ is positive for both values of $x$ which means that the values we found in part (a) are underestimations.

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3 years ago

Solve the system with elimination. {2x-y=2, -5x+4y=-2

DaniilM [7]

Answer:

{x=2,y=2

Step-by-step explanation:

Equation 1:

Multiply both sides of the equation by a coefficient

{ 4(2x-y)=2*4

-5x+4y=-2

Apply Multiplicative Distribution Law

{8x-4y=2*4,-5x+4y=-2

8x-4y+(-5x+4y)=8+(-2)

Remove parentheses

8x-4y-5x+4y=8-2

Cancel one variable

8x-5x=8-2

Combine like terms

3x=8-2

Calculate the sum or difference

3x=6

Divide both sides of the equation by the coefficient of the variable

x=6/3

Calculate the product or quotient

x=2

Equation two:

{-5+4y=-2, x=2

-5*2+4y=-2

Calculate the product or quotient

-10+4y =-2

Reduce the greatest common factor (GCF) on both sides of the equation

-5+2y=-1

Rearrange unknown terms to the left side of the equation

2y=-1+5

Calculate the sum or difference

2y=4

Divide both sides of the equation by the coefficient of the variable

y=4/2

y=2

Hope this helps!!

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2 years ago

Beneficial terms of trade are the terms or prices that are between the two parties' oppotunity costs

nevsk [136]

Answer:

Beneficial terms of trade or trading price between two parties are opportunity costs lower than the cost to manufacture them locally which benefits both parties. They must be less enough to cover the freight charges or additional service charges that may arise.

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3 years ago