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Galina-37 [17]
3 years ago
12

Alina says the area of the rectangular face is 10 in 2 ls

Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

Answer:

No, the face’s dimensions are 4 in. by 6 in., so the area is 24 in.2.

Step-by-step explanation:

she didn't multiply good

Mumz [18]3 years ago
5 0

Answer:

It's B

Step-by-step explanation:

Because I randomly guessed and that was the answer.

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3y + 1.8 ≥ 10.8 I need mad help on dis
soldier1979 [14.2K]

Answer:

In this question the <em>y</em> is 3.

Step-by-step explanation:

3 x 3 is 9.

9 + 1.8 = 10.8

3 0
3 years ago
MATH PROBLEM!! CAN SOMEONE HELP 25pts You roll two number cubes at the same time. Let X be a random variable that represents the
Vesna [10]

Answers:

(a) Possible values of X are: 0, 1, 2, 3, 4, 5

(b) See attached image below; specifically figure 2

(c) No, it is <u>not</u> symmetric

(d) As a fraction, the answer is 1/6. In decimal form, the answer is approximately 0.1667 (converts to roughly 16.67%)

=========================================

Explanations:

(a) The largest possible roll we can get on one die is 6, the smallest is 1, so the largest possible difference is 6-1 = 5. The smallest difference is 0 as we could get doubles (eg: both dice show a "3" at the same time). We can get any difference in between 0 and 5. So X can take on whole numbers from 0 to 5, ie, X can be any number from the set {0, 1, 2, 3, 4, 5}

(b) Consult the attached image. Figure 1 shows a 6 by 6 grid of values that represent all the possible ways to roll two dice. Each value in the interior of the grid is the result of subtracting the outer header values. Figure 2 is where the answer is shown for part b. The idea is that you list out the X values along the top of the table and the probability P(X) values along the bottom row. I show the work on how to compute each probability in the attachment. The probability is equal to the number of occurences over the number total. Example: X = 3 shows up 6 times out of 36, so P(X) is 6/36 = 1/6 when X = 3.

(c) The distribution is not symmetric as figure 3 shows a lop-sided diagram. The mode should be at the center, but this figure shows the mode off to the left side.

(d) Count how many copies of '4' or '5' show up in the interior of the grid shown in figure 1. There are four copies of '4' and two copies of '5'. Overall there are 4+2 = 6 instances of either '4' or '5'. This is out of 36 total, so 6/36 = 1/6 is the fractional form of the answer which approximates to 0.1667 and converts to 16.67% approximately.

4 0
3 years ago
Janet and Nadia each play basketball. Nadia has won twice the number of games Janet has. Is it possible for Janet to have won 10
ladessa [460]

Answer: It is not possible for Janet to have won 10 games.

Step-by-step explanation:

Let be "x" the number of games Janet won.

We know that Nadia has won twice the number of games Janet has and the sum of the games Nadia and Janet have won together is 24.

Then, we express this situation with this equation:

x+2x=24

So, let's check if it is possible for Janet to have won 10 games. Substitute x=10 into the expression:

10+2(10)=24\\\\10+20=24\\\\30=24\ (This\ is\ not\ true)

Therefore, it is not possible for Janet to have won 10 games.

3 0
4 years ago
Read 2 more answers
Find the sum of the first 50 terms below. an=3n+2
andrey2020 [161]

Step-by-step explanation:

1st term = a(1) = 3(1) + 2 = 5

50th term = a(50) = 3(50) + 2 = 152

Sum of first 50 terms = (5 + 152) * (50/2) = 3925.

3 0
3 years ago
3. Thomas argues that a quadrilateral with one pair sides congruent and the other pair
notsponge [240]

Step-by-step explanation:

one pair of side equal and other could be a trapezium as well...

he should have told that the two pair of sides are equal and parallel...

6 0
3 years ago
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