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mamaluj [8]
3 years ago
15

a light bulb consumes 6300 watt hours in 3 days and 12 hours. how many watt hours does it consume per day

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

1800 watt hours

Step-by-step explanation:

6300 watt hours in 3 days and 12 hours

3 x 24 = 72 3 days worthof hours

72 + 12 = 84 total hours

6300/84 = 75 watt hours per hour

75 x 24 = 1800 watt hours per day

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Artist 52 [7]

Answer:

uahabsihsb

Step-by-step explanation:

  1. shahabajwnznjsiay
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7 0
2 years ago
"A laboratory tested 73 chicken eggs and found that the mean amount of cholesterol was 230 milligrams with LaTeX: \sigmaσ = 17.4
Scrat [10]

Answer:

The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{17.4}{\sqrt{73}} = 3.99

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 3.99 = 226.01

The upper end of the interval is the sample mean added to M. So it is 230 + 3.99 = 233.99.

The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.

4 0
3 years ago
I NEED THE ANSWER FOR THIS TEST PLEASE<br><br> Simplify -5+i/2i<br><br> Show work
LenaWriter [7]

\dfrac{-5+i}{2i}=\dfrac{-5+i}{2i}\cdot\dfrac{i}{i}=\dfrac{-5i+i^2}{2i^2}=\dfrac{-5i-1}{2(-1)}=\dfrac{5i+1}{2}=\dfrac{1}{2}+\dfrac{5}{2}i

8 0
3 years ago
Two teachers are taking 8 students to the aquarium. Adult admission is $12, but students receive a discount of $3 off
zhuklara [117]

Answer:

86$

12-3=9

9x8=72

72+14=86$

6 0
3 years ago
The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

So, the probability that a switch fails in the first year is

\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
3 years ago
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