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aleksandr82 [10.1K]
3 years ago
7

Jordan has 10 ties, 3 Suits, 5 Belts, 8 Shirts, and 4 pairs of Shoes that he chooses from daily to select his professional wardr

obe? How many different outfits can he put together? ​
Mathematics
1 answer:
Andre45 [30]3 years ago
3 0

To find the total different outfits, multiply the quantity of each item together:

10 x 3 x 5 x 8 x 4 = 4,800

Answer: 4,800 different outfits

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Using the digits 0 to 9, without repetition, fill the blanks.
Alexandra [31]
First angle to the right inside the triangle can be 60
Other angle inside the triangle can be 40
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The last angle 100
4 0
3 years ago
8x + 2 – 6 = 4x +8 +3x
Viefleur [7K]
The first step is to combine like terms. So u would do 2-6. You then get -4 then u just bring everything else down. So now u should have this :

8x -4 = 4x + 8 + 3x

Now you do the same thing to the other side. U combine like terms which in this case are 4x and 3x. So u just do 4+3 which is 7 so now u have 7x. So now ur equation would be:

8x -4 = 7x +8

Now u do the inverse of 7 which would be -7 and u do that on both sides. So it would look like this :

8x -4 = 7x + 8
-7x. -7x

So now 7 and -7 cancel each other other and 8 -7 is 1 so now u have one x. So ur equation would now look like this:

1x -4 = 8

Now u do the inverse of negative 4 which is +4. So you would add 4 on both sides on both sides. Like shown:

1x -4 = 8
+4 +4

So u just add 8 + 4 which is 12. Now since anything times 1 is itself ur answer will be X=12


Hope this helped



4 0
3 years ago
What is an equivalent expression for the quotient? 4²/4⁵
Lisa [10]

Answer:

\frac{1}{ {4}^{3} }

Step-by-step explanation:

\frac{ {4}^{2} }{ {4}^{5} }  =  \frac{1}{ {4}^{ - 2} \times  {4}^{5}  }  =  \frac{1}{ {4}^{(5 - 2)} }  = \frac{1}{ {4}^{3} }

8 0
3 years ago
at a small school, one male and one female are selected to represent the student body at the PTSCA meetings. if there are 41 mal
I am Lyosha [343]

It is given that there are 41 males and 48 females in the small school.

So, the number of ways a male student can be chosen from 41 males is ^{41}C_1

Likewise, the number of ways a female student can be chosen from 48 females is ^{48}C_1.

Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:

^{41}C_1\times ^{48}C_1=1968


7 0
3 years ago
Adam plans to choose a video game from a section of the store where everything is 75% off. He writes the expression d−0.75d to f
alekssr [168]

Answer:

is 0.75d becase the missing numbers should be the same number

5 0
3 years ago
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