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2 years ago

5.

Mathematics

1 answer:

klemol [59]2 years ago

6 0

The answer is C. . . . . . . . . . . . .

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Order 10,16,18,24,14,17,26,15,14,

Anettt [7]

Order : 6 9 9 10 12 15 15 17 18

Mean: 12.33

Median: 12

mode: 9 and 15

range: 12

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2 years ago

If PQ=7 and QR=10, then PR=

Cloud [144]

Answer:

PR=PQ+QR

=7+10

=17

Hope this will help:)

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2 years ago

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One of the legs of a right triangle measures 2 cm and its hypotenuse measures 19 cm.

pentagon [3]

Answer:

18.9

Step-by-step explanation:

361-4 = 357

the root of 357 is 18.9 when rounded

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2 years ago

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

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2 years ago

What does x mean in maths

Nana76 [90]

X is usually the representation for the unknown number.

3 0

3 years ago

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