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3 years ago

Helppppppppppppppp!!!!!!

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

6 0

Answer:

Trick question

These are NOT three sides to a right triangle

Using the pythagorean theroem, you can prove it

$a^{2} + b^{2} = c^{2}$

$6^{2} +$ $8^{2}$ $=12^{2}$

$36 + 64 \neq 144$

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What is the domain of the square root function graphed below

Lina20 [59]

Answer:

Dominio de una Raíz cuadrada

Cuando tenemos una raíz, para estudiar su existencia debemos saber que una raíz existe si y solo sí el radicando (lo que está dentro de la raíz) sea mayor o igual a cero.

Por lo tanto deberemos estudiar el signo de lo que se encuentra dentro de la raíz; y determinar las zonas positivas y las raíces que son las zona de existencia de la función raíz o dominio de esta función.

Step-by-step explanation:

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5 0

3 years ago

I just need someone to fill in all the answers

Masteriza [31]

Answer:

1. 2

2. 25

3. 1/3

I'm in 8th grade so not 100% sure about these

I'm gonna try the rest

But this is what I got so far!

3 0

3 years ago

What are the zeros of this function?

tatyana61 [14]

Answer:

Step-by-step explanation:

the zeroes of a function basically mean when y = 0, so basically the x-intercept(s)

in this case, the zeroes are 3 and 6

3 0

3 years ago

Read 2 more answers

Neeeedhelp asap !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

slavikrds [6]

Answer:

1. $0.24

2. 89.2 miles

Step-by-step explanation:

To get the unit price, divide the total price by the amount that was purchased.

1. 3.12/13 = $0.24

For the second one, get the distance traveled per hour first then multiply by 8.

22.3 / 2 = 11.15

11.15 x 8 = 89.2

6 0

3 years ago

How do I simplify this (sinx)/(secx+1)

pochemuha

Answer:

Step-by-step explanation:

$\frac{sin~x}{sec~x+1} =\frac{sin~x}{\frac{1}{cos~x}+1 } =\frac{sin~x~cos~x}{1+cos~x} \\=\frac{sin~x~cos~x}{1+cos~x} \times \frac{1-cos~x}{1-cos~x} \\=\frac{sin~x~cos~x(1-cos~x)}{1-cos^2 x} \\=\frac{sin~x~cos~x(1-cos~x)}{sin^2x} \\=\frac{cos~x(1-cos~x)}{sin~x} \\=cos ~x(csc~x-cot~x)\\or\\=cot~x(1-cos~x)$

6 0

4 years ago