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2 years ago

Can you please help me please I really need help

Mathematics

1 answer:

RoseWind [281]2 years ago

5 0

Answer:

(look below)

Step-by-step explanation:

i used to do ixl so heres an appropriate answer:

1 21

3 63

5 105

7 147

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Mrs. Johnson wants to take her class to the fair. The bus will cost $200 and the fair charges $4 per student. She has a $300 bud

omeli [17]

Answer:

This is simple,

Step-by-step explanation:

If the bus costs 200$ and the fair charges 4$ per students that means you have to do this:

300$ budget - 200 of the bus = 100$ left

and if $4 per student:

100 divided by 4 = 25

she can take 25 students

Hope this helps!

5 0

3 years ago

Unit rate of 72 ounces for 12 servings

Anarel [89]

Ok this is really easy if you thinl about it
so every ounce is how many servings?
well all you do is divide 72 by 12
happy solving :)

4 0

3 years ago

Read 2 more answers

Michael and Lindsey are saving money. Michael begins with $20 and saves $5 per week. Lindsey begins with no money, but saves $10

True [87]

Let
x----------> number of weeks
y----------> saved money

we now that

Michael begins with $20 and saves $5 per week
so
y=20+5x------> equation 1

and
Lindsey begins with no money, but saves $10 per week
y=10x-------> equation 2

the number of weeks it will take for Lindsey and Michael to save the same amount of money is when equation 1 is equals to equation 2

therefore
20+5x=10x------> 10x-5x=20------> 5x=20-----> x=20/5-----> x=4 weeks

the answer is
4 weeks

3 0

3 years ago

Pat has a fever.His temperature is 99.3F. If the conversation is Celsius is C=5/9(F-32), what is the most accurate measurement o

Dmitriy789 [7]

Answer:

37.4

Step-by-step explanation:

7 0

3 years ago

Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

3 0

3 years ago