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3 years ago

Heres 20p for whoever solves this

Mathematics

1 answer:

Leokris [45]3 years ago

6 0

Answer:

i dont remember how to answer this so heres some info from the graph.

the y-intercept of the first equation is 8.

the y-intercept of the second equation is 18.

the equations cross at (10,4)

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Giving brainlist for correct answer. :))

Katena32 [7]

Answer:

162 cubes

Step-by-step explanation:

The formula for finding the volume of a rectangular prism is length x width x height.

6 x 3 x 4.5 = 81

Since each cube is only half a centimeter, we need to multiply this by two.

81 x 2 = 162 cubes

8 0

1 year ago

What is the square root of 1,331

BartSMP [9]

Answer:

Step-by-step explanation:

36.4828727

7 0

2 years ago

Read 2 more answers

10.3.23

Helga [31]

Answer:

The probability that a high school member selected at random is on the swim team is $\frac{9}{40} = 0.225$

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: High school student.

Event B: Is on the swin team.

Probability of selecting a high school student:

Of the 1500 students, 200 are on high school. So

$P(A) = \frac{200}{1500}$

Probability of selecting a high school student who swims:

Of the 1500 students, 45 are high school students who swim. So

$P(A \cap B) = \frac{45}{1500}$

What is the probability that a high school member selected at random is on the swim team?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{45}{1500}}{\frac{200}{1500}} = \frac{45}{200} = \frac{9}{40} = 0.225$

The probability that a high school member selected at random is on the swim team is $\frac{9}{40} = 0.225$

4 0

2 years ago

A concentric-tube heat exchanger cools hot water owing at 1 kg/s from 80C to 30C. It uses air owing at 5 kg/s to perform this co

nordsb [41]

Answer:

The log-mean-temperature-difference is 24.03⁰C

Step-by-step explanation:

First we need to know if the heat exchanger is in parallel flow or counter-flow. However, counter flow arrangement is best used to recover heat.

L.M.T.D for counter flow is given as;

$L.M.T.D =\frac{(T_h_f_1 -T_c_f_2)-(T_h_f_2 -T_c_f_1)}{2.3log[\frac{T_h_f_1 -T_c_f_2}{T_h_f_2 -T_c_f_1}]}$

where;

Thf₁ is the initial temperature of the hot fluid = 80°C

Tcf₂ is the final temperature of the cold fluid = 51.5°C

Thf₁ - Tcf₂ = 80 - 51.5 = 28.5⁰C

Thf₂ is the final temperature of the hot fluid = 30°C

Tcf₁ is the initial temperature of the cold fluid = 10°C

Thf₂ - Tcf₁ = 30 - 10 = 20⁰C

$L.M.T.D = \frac{28.5 -20}{2.3Log[\frac{28.5}{20}]} \\\\L.M.T.D = \frac{8.5}{0.3538} =24.03^oC$

Therefore, the log-mean-temperature-difference is 24.03⁰C

3 0

2 years ago

Read 2 more answers

Let a = 3; x = 2<br><br>c) y = ( a * x ) * x * ( x + 7 )

Molodets [167]

Step-by-step explanation:

please mark me as brainlest

6 0

3 years ago