Answer:
z=5
Trust me I don't know how to explain it.
Based on the bisection of line BC by point A, the value of x is 10/3
<h3>How to determine the value of x?</h3>
The given parameters are:
- Point A bisects BC
- BA = 6x - 3
- AC= 3x + 7
Because the point A bisects BC, then
BA = AC
Substitute the known values in the above equation
So, we have
6x - 3 = 3x + 7
Collect the like terms
6x - 3x = 3 + 7
Evaluate the like terms
3x = 10
Divide both sides of the equation by 3
x = 10/3
Hence, based on the bisection of line BC by point A, the value of x is 10/3
Read more about bisectors at:
brainly.com/question/6725549
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To find the value of a variable you must know the basics of pre-Algebra.
Example:
2x+9=39
To find he answer of this you must subtract 9 from both sides
Then you are left with…
2x=30
Since 2x=30 means 2 times x equals 30
You can divide 2 from both sides to find the answer
Which is…
x=15
This most definitely has to be a rhombus since it is a form of a square with 4 congruent sides where a rectangle only has 4 right angles.
To clarify, a trapezoid only has one pair of parallel sides if you were wondering.
Answer:
10x - 3y = -109 .
Step-by-step explanation:
x^2 + y^2 = 109
Implicit Differentiation:
2x + 2y.y' = 0
y' = -2x/2y = -x/y
So at the point (-10,3) the gradient of the tangent is -(-10)/3 = 10/3.
Equation of the tangent:
y - y1 = m(x - x1)
y - 3 = 10/3(x + 10)
y - 3 = 10/3 x + 100/3
3y - 9 = 10x + 100
-109 + 3y = 10x
10x - 3y = -109