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Evgesh-ka [11]
3 years ago
15

21➗7= , ✖️7=21 what is the meaning of the unknown factor and quotient?

Mathematics
1 answer:
viktelen [127]3 years ago
5 0
21 divided by 7 equals 3 and 3 x 7 is 21 the missing factor is 3 and the missing quotient is 21
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Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that s
Gwar [14]

Answer:

c=2

Step-by-step explanation:

All polynomials are continuous and differentiable on the set of real numbers.

So we just need to confirm on the given interval that f(1)=f(3).

f(1)=1-12(1)+3(1)^2

f(1)=1-12+3

f(1)=-8

f(3)=1-12(3)+3(3)^2

f(3)=1-36+27

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So this means there is c in (1,3) such that f'(c)=0.

To solve that equation we must differentiate.

f(x)=1-12x+3x^2

f'(x)=0-12+6x

f'(x)=-12+6x

Remember we need yo solve f'(c)=0 for c.

So we need to solve -12+6c=0.

-12+6c=0

Add 12 on both sides:

6c=12

Divide both sides by 6:

c=2

6 0
4 years ago
The mass of a piece of iron pyrite, or "fools gold", is 57.2 g. The volume is 11 cm3. What is the density of the piece of iron p
katen-ka-za [31]

Answer:

<h2>5.2 g/cm³</h2>

Step-by-step explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{57.2}{11}  = 5.2 \\

We have the final answer as

<h3>5.2 g/cm³</h3>

Hope this helps you

3 0
3 years ago
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EleoNora [17]

Answer:

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Help me i need a 60 or above
BARSIC [14]

Answer:

See below.

Step-by-step explanation:

12(3d+8)

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6 0
2 years ago
Read 2 more answers
An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra
Ket [755]

Answer:

The area is changing at the point of  \mathbf{61200 m^2/year}

Step-by-step explanation:

From the given information:

Let's recall from our previous knowledge that the formula for finding the area of a rectangle = L × w

where;

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Suppose the Length L is twice the width w

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Replacing the values back into equation 2, we get:

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