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2 years ago

9

Bakery shop offers a special price on the pastries on Monday and Sunday each donut cost the same and each cookie cost of saying

the price of donuts and cupcakes is different on Monday the bakery sold 52 donuts in 22 cupcakes for a total of $138.50 what is the cost of each cupcake

1 answer:

Effectus [21]2 years ago

3 0

You have to estimate so it’s about 6 dollars for each cupcake (thank me later

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Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

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$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

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3 years ago

If Ryan gives 2/6 of his 36 cards to Max, how many cards does he give Max?

diamong [38]

Answer:

Hi there

Your answer is

He gives Max 12 cards

Step-by-step explanation:

2/6 of 36

2/6 * 36/1

72/6=12

12 cards is 2/6th of 36 cards

4 0

3 years ago

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Which value of x is in the solution set of the inequality -3x+5>17?

shepuryov [24]

-3x + 5 > 17 |subtract 5 from both sides

-3x > 12 |change the signs

3x < -12 |divide both sides by 3

<h3>x < -4</h3>

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3 years ago

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Sloan [31]

Answer:

A

Step-by-step explanation:

Please see the attached picture for full solution.

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3 years ago

oksian1 [2.3K]

Answer:

$t= 6\ s$

Step-by-step explanation:

We know that the equation that models the height of the ball as a function of time is $h(t) = -16t ^ 2 + 80t + 96$ .

Where the initial speed is 80 feet.

When the ball lands on the ground, its height will be $h(t) = 0$ .

So to know how long it will take the ball to reach the ground, equal h (t) to zero and solve for t.

$-16t ^ 2 + 80t + 96 = 0$

To solve this quadratic equation we use the quadratic formula.

For an equation of the form:

$at^2 +bt +c$

The quadratic formula is:

$t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}$

In this case

$a =-16\\b = 80\\c =96$

Then

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7 0

3 years ago

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