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aliina [53]
3 years ago
11

Find the area 96 sq meters 144 sq meters 84 sq meters 102 sq meters

Mathematics
2 answers:
Veronika [31]3 years ago
7 0
The answer is 84 sq meters
Vsevolod [243]3 years ago
4 0

Answer:

the answer is 84.... .....

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answer #14 for me plss and thank you!!!!​ pls do not answer if you don't know the answer just comment
olga_2 [115]

Answer:

2, 3

Step-by-step explanation:

The graph of quantities in direct proportion.

Is a straight line passing through the origin, thus

the line always crosses the y- axis at |(0, 0 )

Thus the y- intercept is 0

3 0
3 years ago
What is the equivalent factored form of 12x^4-42x^3-90x^2
Tanzania [10]
Factor the following:
12 x^4 - 42 x^3 - 90 x^2

Factor 6 x^2 out of 12 x^4 - 42 x^3 - 90 x^2:
6 x^2 (2 x^2 - 7 x - 15)

Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
6 x^2 x (2 x + 3) - 5 (2 x + 3)

Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
Answer:  6 x^2 (2 x + 3) (x - 5)
4 0
3 years ago
Read 2 more answers
At the last minute, the technology company decides to expand the warehouse and asks the general contractor to double the dimensi
Lesechka [4]
<span>The expansion of the warehouse will not affect the dimensions of the surrounding fence.</span>
3 0
3 years ago
Solve the expression using pemdas (4+5)÷3×4​
Dennis_Churaev [7]

1) you add the variables in the bracket

(4+5)÷3×4

9÷3×4

2) you multiply 3 by 4

9÷3×4

9÷12

3) now you divide 9 by 12

9÷12

=0.75

7 0
3 years ago
Read 2 more answers
At time​ t, the position of a body moving along the​ s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m. a. Find t
larisa [96]

Answer:

Step-by-step explanation:

Given that at time t, the position of a body moving along the​ s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m

i.e. s(t) = -t^3+15t^2-72 t

Velocity is nothing but s'(t) = derivative of s

and acceleration is s"(t) = derivative of v(t)

v(t) = -3t^2+30t-72\\=-3(t^2-10t+24)\\= -3(t-6)(t-4)

a) v(t) =0 when t = 4 or 6

b) a(t) = -6t+30

a(t) =0 when t =5

c) Distance travelled by the body from 0 to 5 would be

s(5)-s(0)\\= -5^3+15(5^2)-72(5)\\= -125+375-360\\=-110

i.e. 110 miles (distance cannot be negative)

3 0
3 years ago
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