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Reika [66]
2 years ago
13

name a twich stremer tha has at least has 1k view each and has a YoTube channel that i might not know about also what is the val

ue of 20+3(7+4)+5+2(7+9)​
Mathematics
2 answers:
Aloiza [94]2 years ago
8 0

Answer:

76

Step-by-step explanation:

Use PEMDAS

Parenthesis first then add

lions [1.4K]2 years ago
7 0

Answer:

The answer is down below

Step-by-step explanation:

90

You might be interested in
500 ML = __ L<br><br> Perform numerical calculations
prohojiy [21]

Answer:

500*10^6 L or 5.00*10^8 L.

Step-by-step explanation:

Capital M shows mega which equal to 10^6.

So, 500 ML = 500*10^6 L

or 5.00*10^8 L.

3 0
3 years ago
Read 2 more answers
A coin is tossed, and a die is rolled. Find the probability of getting heads and then rolling a 6.
Colt1911 [192]

Answer:

1/2 and 1/6

Step-by-step explanation:

8 0
2 years ago
The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti
melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that m = 100, \mu = \frac{1}{100} = 0.01

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

P(X > x) = e^{-\mu x}

This is P(X > 190). So

P(X > 190) = e^{-0.01*190} = 0.1496

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

P(X > x) = 0.08

So

e^{-0.01x} = 0.08

\ln{e^{-0.01x}} = \ln{0.08}

-0.01x = \ln{0.08}

x = -\frac{\ln{0.08}}{0.01}

x = 252.6

Capacity of 252.6 cubic feet per second

5 0
3 years ago
J) You spend $35. Tip is 15%. How much did you pay in total?
rusak2 [61]

Answer:

You paid $40.25 in total.

Step-by-step explanation:

In this question:

Spending of 35%

Tip of 15% means that 15% of 35 will be added to your total spending. So

T = 35 + 0.15*35 = 35 + 5.25 = 40.25

You paid $40.25 in total.

3 0
3 years ago
What is the equation of the line that passes through (4, 3) and (2, 2)?
anastassius [24]
(4,3)(2,2)
slope = (2 - 3) / (2 - 4) = -1/-2 = 1/2

y = mx + b
slope(m) = 1/2
use either of ur sets of points...(4,3)...x = 4 and y = 3
now we sub and find b, the y int
3 = 1/2(4) + b
3 = 2 + b
3 - 2 = b
1 = b

so ur equation is : y = 1/2x + 1 <==
4 0
3 years ago
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