Answer:
Step-by-step explanation:
Given (64 y Superscript 100 Baseline) Superscript one-half.
Let us write it into an equation.
Apply radical rule: and
Hence, is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.
Answer:
4:18 8:36 1:4.5
Step-by-step explanation:
Answer:
A. Definition of angle bisector
Step-by-step explanation:
Given that ΔABC is an isosceles triangle where AB = BC, and that BD bisects ∠ABC, then by the definition of angle bisection of ∠ABC, we have;
m∠ABD = m∠CBD
The correct option is option A. Definition of angle bisector
<em>Also, given that ΔABC is an isosceles triangle and BD is the angle bisector of ∠ABC, we get;</em>
<em>AD = CD and BD = BD</em>
<em>We can therefore, also find that ΔABD ≅ ΔCBD by Side Side Side (SSS) rule of congruency</em>
Randall's bag: 68 pounds
Seth's bag: 40 pounds
Joanna's bag: 52 pounds
Step-by-step explanation:
Given,
Randalls bag: 3x-7 pounds
Seth's bag: 2x-10 pounds
Joanna's bag: 2x+2 pounds
Also given that,
Randall's and Joanna's bags weigh 3 times as much as Seth's bag. Therefore
(Randall's bag + Joanna's bags) = 3* (Seth's bag)
By putting the values in equation, we get:
(3x - 7 + 2x + 2) = 3* (2x - 10)
=> (5x - 5) = (6x - 30)
=> -5 + 30 = 6x - 5x
=> 25 = x
or
x = 25
We can get the thrash weight of each friend after putting the value of x
Randalls bag: 3x-7 = 3(25) - 7 = 75 -7 = 68 pounds
Seth's bag: 2x-10 = 2(25) - 10 = 50 - 10 = 40 pounds
Joanna's bag: 2x+2 = 2(25) +2 = 50 + 2 = 52 pounds
Answer:
is there a possibility you could show a picture please?