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3 years ago

Help! Sorry if it’s hard to see it would not look different everytime I retook the picture! :)

Mathematics

1 answer:

pshichka [43]3 years ago

5 0

Answer:

d = 11.401754

For:
(X1, Y1) = (5, 4)
(X2, Y2) = (-4, -3)

Distance Equation Solution:

=√ (-4−5)2+(−3−4)2

=√ (-9)2+(−7)2

=√ 81+49

=√ 130

=11.401754

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The sum of two numbers is 75. The second number is 3 less than twice the first

Mandarinka [93]

Answer:

$\large{\textbf{The two numbers are: 26 and 49}.\\}$

Step-by-step explanation:

$\large{\textup{assume the two numbers are $x$ and $y$.}}\\\large{\textup{The given sentences are written in mathematical terms as follows:}\\$$ x + y = 75 \hspace{25mm} (1)$$ $$ y = 2x - 3 \hspace{25mm} (2) $$ \\\textup{Substituting $(2)$ in $(1)$,}\\\begin{align*} & \implies x + 2x - 3 = 75 \\& \implies 3x = 78 \\& \implies x = 26\end{align*}\textup{Substituting $x$ in $(1), \hspace{5mm} y = 49$} }$

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3 years ago

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Answer:

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3 years ago

Chad wants to buy some books over the Internet. Each book costs $10.01 and has a shipping cost of $9.96 per order. If Chad wants

inysia [295]

Answer:

9.96 + 10.01p ≤ 50, so p ≤ 4

Step-by-step explanation:

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3 years ago

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What is the equation of the line that passes through the point (-4,2) and has a slope of 1/4

zubka84 [21]

Step-by-step explanation:

Equation of line is y-y1 = m(x-x1), where m is the slope and (x1,y1) is the given point.

y-2 = 1/4*(x-(-4))

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2 years ago

Q1.Simplify:

solniwko [45]

$\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\$

$\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\$

$\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625$

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2 years ago

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