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guajiro [1.7K]
2 years ago
7

Find the values of a and b​ please I will mark brainliest. (make sure to show your work)​

Mathematics
1 answer:
alexdok [17]2 years ago
6 0

Answer:

a = 29

b = 20

Step-by-step explanation:

2a - 1 = 57

    + 1     + 1

2a = 58

/ 2    / 2

a = 29

2a - 1 + 7b - 17 = 180

2 (29) - 1 + 7b - 17 = 180

58 - 1 + 7b - 17 = 180

57 + 7b - 17 = 180

7b + 40 = 180

      - 40     - 40

7b = 140

/ 7      / 7

b = 20

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Mohit pays rupees 9000 as an amount on the sum of rupees 7000 that he had borrowed for 2 years.
Sphinxa [80]

Answer:

The required rate of interest   =   14.285%

Step-by-step explanation:

Here, The principal amount = 7,000

The final paid amount = 9,000

Time = 2 years

Let us assume the rate of interest = R

Now, Simple Interest  =  Amount - Principal

                                      =  9,000 - 7,000  = 2,000

So, the SI on the given principal for 2 years  = 2,000

\textrm{SIMPLE INTEREST } = \frac{P \times  R \times T}{100}\\\implies 2000 = \frac{7,000 \times  R \times 2}{100}\\\implies R = \frac{2,000 \times 100}{7,000 \times 2}  = 14.285

or, R =  14.285%

Hence, the required rate of interest   =   14.285%

8 0
3 years ago
Let n (AUB)=32n(B)=16and n(ANB)9 find n (A)​
Lubov Fominskaja [6]

Answer:

32

Step-by-step explanation:

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)= ? we represent with x

n(B)= 16

n(A∪B) = 32

Substituting in equation 1 to get n(A)

32  = n(A) + 9 − 9

⇒n(A) = 32 − 0

n(A)  = 32

to confirm this we put the values into the formula below

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

32 =  32 + 9 - 9

4 0
2 years ago
Read 2 more answers
Please help with this question please
puteri [66]

Answer:

Choice A

Step-by-step explanation:

(4m^5n^2/m^2n)^3

dividing exponents = subtraction

(4m^3n)^3

4^3 = 64

(m^3 )^3 = m^3x3 = m^9

64m^9n^3

5 0
3 years ago
The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent.Find the single reduction the
Evgen [1.6K]

Answer:

40%  . The single reduction together is 40%.

Step-by-step explanation:

Let the bicycle cost is   x before reduced price.

First 25% is reduced  and again 20% further reduced.

Let the single reduction is y% if the two reduction together are equal.

Solution,

Case .1

reduction cost=x\times 25%%

=x\times 25/100

=x/4

The cost of bicycle after reduction of 25% is

=x-x/4=3x/4

cost of reduction further reduction of 20%      =3x/4\times 20%

=3x\times 20/(4\times 100)

=3x/20

The new cost of bicycle is further reduction of 20% is

=3x/4-3x/20

=\left ( 15x-3x \right )/20

=12x/20=3x/5

Case.2

if single reduction is done new cost of cycle is equal

x-x\times y%=3x/5

x\left ( 1-y/100 \right )=3x/5

\left ( 100-y \right )/100=3/5

100-y=60

y=40%

single reduction of a cycle is 40%

8 0
3 years ago
Solve for y 16y^2-25=0
Pepsi [2]

Answer:

\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

Step-by-step explanation:

16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}

METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

7 0
3 years ago
Read 2 more answers
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