Answer:
<h2>
<em>1</em><em>5</em><em> </em><em>units</em></h2>
<em>The </em><em>length </em><em>of </em><em>BC </em><em>is </em><em>1</em><em>5</em><em> </em><em>units.</em>
<em>Solution,</em>
<em>Hypotenuse(</em><em>h)</em><em>=</em><em>?</em>
<em>perpendicular(</em><em>p)</em><em>=</em><em>1</em><em>2</em>
<em>base(</em><em>b)</em><em>=</em><em>9</em>
<em>Using </em><em>Pythagoras</em><em> </em><em>theorem</em><em>,</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
$80 dollars
Step-by-step explanation:
Answer:
No solution
Step-by-step explanation:
As 6x on lhs and 2×3x on the rhs are equal and cancel each other
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
Answer:
63
Step-by-step explanation:
Given:
a set of six elements
The solution would be like this for this specific problem:
number of subsets of n elements = 2^n
(2^6) - 1
= 64 – 1
= 63
