What is the difference of the lengths of and ? use the value = 3.14, and round the answer to two decimal places. a. 1.25 units b
1 answer:
The difference between the length of arc BD and CE is 1.57 units
<h3>Length of an arc</h3>length of arc = ∅ / 360 × 2πr
where
- r = radius
- ∅ = central angle
Therefore,
BD = 45 / 360 × 2 × 3.14 × 6 = 1695.6 / 360 = 4.71 units
CE = 45 / 360 × 2 × 3.14 × 8 = 2260.8 / 360 = 6.28 units
Therefore, the difference between the length of arc BD and CE is as follows:
6.28 - 4.71 = 1.57 units
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Answer:
u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩
u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩
Step-by-step explanation:
for a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩
a vector orthogonal to a and b can be found through the vectorial product of a and b. Thus
c= a x b
then c₁=⟨2,−10,−22⟩ and c₂= - c₁= ⟨-2,10,22⟩ are orthogonal to a and b
the corresponding unit vectors are
u₁=c₁/|c₁| = ⟨2,−10,−22⟩ / √(2²+(−10)²+(−22)²) = ⟨2,−10,−22⟩/(14*√3) = ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩
then u₂= - u₁= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩
then the unit vectors are
u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩
u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩