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andrey2020 [161]
3 years ago
9

The answer is D!!Readable code includes

Computers and Technology
2 answers:
lana66690 [7]3 years ago
6 0

Answer:

D

Explanation:

says in title

nikitadnepr [17]3 years ago
3 0
Ok but don't understand.
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Given an array temps of double s, containing temperature data, compute the average temperature. Store the average in a variable
Ket [755]

Answer:

#include <iostream>

using namespace std;

// average function

void average(double arr[], int n) {

double total = 0;

double avgTemp;

for (int i = 0; i < n; i++)

{

 // find temperatures total

 total = total + arr[i];

}

// find average

avgTemp = total / n;

cout << "\nAverage Temperature = " << avgTemp << endl;

}

// print temps[] array

void printArray(double arr[], int n) {

for (int i = 0; i < n; i++)

{

 cout << arr[i] << "   ";

}

}

int main() {

int const k = 5;

double temps[k];

// temperature value

double tempValue;  

// Enter 5 temperatures of your choice

for (int i = 0; i < k; i++)

{

 cout << "Enter Temperature value " << i+1 << ": ";

 cin >> tempValue;

 temps[i] = tempValue;

}

// Function call to print temps[] array

printArray(temps, k);  

// Function call to print average of given teperatures

average(temps, k);        

return 0;

}

Explanation:

• Inside main(), int constant k is created to set the maximum size of array temps[].

• tempValue of  type double takes value at a given index of our temps[] array.

• the for loop inside main() is used to get tempValue from the user and store those values in our array temps[].

• after that printArray() function is called. to pass an array to a function it requires to perimeters 1) name of the array which is temps in our case. 2) maximum number of the index which is  k.

• note the syntax of void average(double arr[], int n). Since we are passing an array to the function so its formal parameters would be arr[] and an int n which specifies the maximum size of our array temps[].

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