Ask question

Ask question

All categories

2 years ago

15

Expand & simplify 5 ( p + 6 ) − 5 ( p − 2 )

1 answer:

HACTEHA [7]2 years ago

8 0

Answer: 0p + 40

Step-by-step explanation:

5p + 30 - 5p + 10

0p + 40

You might be interested in

How do I unsubscribe from here

Naddik [55]

Answer:

usub from where

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

2 years ago

Help plzzzzzz 10 point question

Rus_ich [418]

Danville,Keflavik,Somerville,Ulsan,,Smithfield

5 0

3 years ago

Read 2 more answers

If 0.5% of a number is 250, find the number

kaheart [24]

0.5% or 1/2% of say "x" is 250, whilst "x" is the 100%.

$\begin{array}{ccll} \%&amount\\ \cline{1-2} \frac{1}{2}&250\\[1em] 100&x \end{array}\implies \cfrac{~~ \frac{1}{2}~~}{100}=\cfrac{250}{x}\implies \cfrac{1}{200}=\cfrac{250}{x}\implies x = 50000$

6 0

2 years ago

Read 2 more answers

What does 3.92 × 0.051 equal. Plz explain how u found the answer to me

DerKrebs [107]

0.19992 because u need to times the digits

3 0

3 years ago

Read 2 more answers