Answer:
A =19.5
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin A= opp/ hyp
sin A = 3/9
Take the inverse sin of each side
sin ^-1 sin A = sin ^-1 (3/9)
A =19.47122063
To the nearest tenth of a degree
A =19.5
we are supposed to find
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.
The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.
In a parallelogram The opposite angles and opposite sides are always equal.
Hence the correct option is
The diagonals are congruent.
Answer:
Area=15
Perimeter=16
Step-by-step explanation:
First, section the shape off by easier work with shapes.
The two end triangles can then form one large rectangle that is 5in. x 3in.
Next just multiply the length times the width for the area which is 15 in., and add all of the sides up, which will give you 16 in.
Hi there!
We are asked to use the distributive property to rewrite the expression 6(5 - q). Using the distributive property, we get 6(5) - 6(q). When we simplify, we get 30 - 6q, which is our answer. Hope this helps!
