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3 years ago

Factorising what is 9+12y+123r

Mathematics

2 answers:

marshall27 [118]3 years ago

8 0

Answer:

3(3+4y+41r)

Step-by-step explanation:

Im pretty sure, usually this stuff is hard for me but this one wasnt.

guajiro [1.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

3(3+4y+41r)

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Can you help me please?

iren [92.7K]

Finding the volume of a cube involves multiplying with this formula.

Height * Width * Length = volume

To find what the side lengths are, we can take the cube root of 64.

∛64 = 4

Height = 4

Width = 4

Length = 4

These sides are multiplied together to get 64.

The only answer choice that makes sense is Option A.

______

Best Regards,

Wolfyy :)

6 0

3 years ago

Read 2 more answers

Passes through (4,-5), slope = 3/4

Alchen [17]

Equation = y = mx + b
y = 3/4x + b

Calculation for b.,
-5 = 3/4 * 4 + b
b = -5/3

So, your final answer is y = 3/4x - 5/3

Hope this helps!

3 0

3 years ago

(x-2)times (x^2+8x-1)

DerKrebs [107]

Answer:

x^3+6x^2-17x+2

Step-by-step explanation:

(x-2)*(x^2+8x-1)

=x(x^2+8x-1)-2(x^2+8x-1)

=x^3+8x^2-x-2x^2-16x+2

collect like terms

= x^3+6x^2-17x+2

6 0

3 years ago

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

3 years ago

I need help with 175 divided by 0.3

elena-14-01-66 [18.8K]

Answer:

583.333333333

583.3

8 0

3 years ago

Read 2 more answers