8/10 of the students in the art class are painting.
1/2=5/10
5/10+3/10=8/10
Answer:
<em>16.8 cubic centimeter</em>
Step-by-step explanation:
Dimensions of rectangular prism are:
To find:
The volume of rectangular prism in cubic cm ?
Solution:
The formula for volume of prism is given as:
Where 
is the length of rectangular prism
is the width of rectangular prism
is the height of rectangular prism
Here we are given the three dimensions of prism as:
Length, = 4 cm
Width, = 3 cm
Height, = 1.4 cm
Putting the values in formula for volume:
So, volume is <em>16.8 cubic centimeter</em>.
The speed is the change in position divided by the time.
There are four intervals where the speed is uniform:
1) from 0 to 0,5 hours
2) from 0,5 hours to 3 hours
3) from 3 to 4 hours
4) from 4 to 7 hours
We are asked to say the average speed during the interval in which J. is traveling the fastest.
That is where the is more inclined, and that happen in the last interval. There the speed is tha change in position / the time =
(200 -0)miles/3hours = 67 mph.
If you are not sure that this is the fastest speed, you can calculate the speed in the other intervals in the same way and compare.
<h3>
Answer: y = 5</h3>
==============================================================
Explanation:
For any rectangle, the diagonals are always the same length. We can use congruent triangles to prove this.
This means AC = BD.
Also, the diagonals of a rectangle cut each other in half (bisect). This indicates the following two equations
We'll use that second equation along with BP = -2x+23 and DP = 3y-6 to form the equation -2x+23 = 3y-6. This will be used later.
---------------
By the segment addition postulate, we know that
BP+DP = BD
(-2x+23)+(3y-6) = BD
BD = -2x+3y+17
Since the diagonals are equal, we also know that AC = -2x+3y+17
We are given that AC = 2x+4
Equating the two right hand sides leads to the equation 2x+4 = -2x+3y+17
---------------
The conclusion of each the last two sections was the following two equations
- -2x+23 = 3y-6
- 2x+4 = -2x+3y+17
We have two equations and two unknowns. We have enough info to be able to find x and y.
Let's isolate 3y in the first equation
-2x+23 = 3y-6
3y-6 = -2x+23
3y = -2x+23+6
3y = -2x+29
Then we can plug this into the second equation
2x+4 = -2x+3y+17
2x+4 = -2x+(3y)+17
2x+4 = -2x+(-2x+29)+17 .... replace 3y with -2x+29
Now solve for x
2x+4 = -2x+(-2x+29)+17
2x+4 = -2x-2x+29+17
2x+4 = -4x+46
2x+4x = 46-4
6x = 42
x = 42/6
x = 7
We then use this to find y
3y = -2x+29
3y = -2(7)+29
3y = -14+29
3y = 15
y = 15/3
y = 5
