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attashe74 [19]
3 years ago
7

Henry subracts 16 from it and gets an answer of 13.9 what was the orginal number​

Mathematics
2 answers:
sergiy2304 [10]3 years ago
5 0

Answer:

29.9 is the answer for that question

Sati [7]3 years ago
5 0

Answer:

the original number would have been 29.9

Step-by-step explanation:

13.9+16=29.9

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Use the Pythagorean Theorem to find an approximate value of x
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Answer:

Step-by-step explanation:

Hypotenuse² =base² + altitude²

(3x + 4)² = (2x + 1)² + (3x)²

{Use (a+b)² = a² + 2ab + b²}

(3x)² + 2*3x+4 + 4² = (2x)² + 2*2x*1 + 1² + 9x²

9x² + 24x + 16 = 4x² + 4x + 1 + 9x²

9x² + 24x + 16 = 13x² + 4x + 1

0 = 13x² + 4x  + 1 - 9x²  - 24x - 16

13x² - 9x² + 4x - 24x +1 - 16 = 0

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D = b² - 4ac  = (-20)² - 4*4*(-15) = 400 + 240 = 640

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x=\dfrac{-b+\sqrt{D}}{2a} \ ; \ x=\dfrac{-b-\sqrt{D}}{2a}\\\\\\x=\dfrac{20+25.30}{2*4} \ ; \ x=\dfrac{20-25.30}{2*4}\\\\\\x=\dfrac{45.30}{8} \ ; \  x =\dfrac{-5.30}{8}\\\\

x = 5 .66   ; x = -0.66

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7 0
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hichkok12 [17]
The answer to the question

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3 years ago
17 less than 12 times a certain number (m) IS 23 less than six times the same
REY [17]

Answer:

  m = -1

Step-by-step explanation:

12 times the number is 12m

17 less than that is 12m -17.

23 less than 6 times the number is 6m-23.

These expressions  are said to be the same:

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  6m -17 = -23 . . . . . . . . subtract 6m from both sides

  6m = -6 . . . . . . . . . . add 17 to both sides

  m = -1 . . . . . . . . . divide both sides by 6

The value of m is -1.

3 0
3 years ago
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ratelena [41]
(x^12)^5=x^(12*5)=x^60
(x^(-2))^9=x^(-18)
x^60*x^(-18)=x^(40) and we need to find x^a such that
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x^a=x^(40)^5*x^(-42)
x^a=x^(200)x^(-42)
x^a=x^(200-42)
x^a=x^158
so the missing term is x^158
6 0
3 years ago
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Degger [83]

The range of a function is the set of the all values taken by the function, for all possible inputs.

When you watch this from a graphical point of view, the range is the portion of the y axis that the graph spans.

In this case, you can see that the lowest point reached by the function (its minimum) is (3,-2). You can also see that the function is unbounded upwards.

So, the range is [2,\infty), and the lowest value is thus 2.

7 0
4 years ago
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