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snow_tiger [21]
2 years ago
14

What is the approximate area of the circle shown?

Mathematics
1 answer:
lord [1]2 years ago
3 0

Answer:

theres no circle shown lol

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Help please on this question. I appreciate it =) <br><br> more than one answer
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I'm pretty sure A, and C but I'm not very sure about B I hope that helped.
4 0
3 years ago
steve has 75.50$ to spend at the movies. His ticket is 45.50? and he gets a large popcorn and soda. If the popcorn and soda each
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$15. 75.5 - 45.5 = 30.

30/2 = 15
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What is the answer to this?
bekas [8.4K]

Answer:

21

Step-by-step explanation:

3 x 7 is 21

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3 years ago
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Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
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