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bija089 [108]
3 years ago
13

Middle School Math

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0

Answer:

The shark is now 40 feet below the surface

Step-by-step explanation:

32-5=27

27+13=40

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Can 14, 18, and 31 form a triangle ?
guapka [62]

Answer: Yes, they can.

Clarification:

We have three different sides with different lengths:

\mathrn {14, 18, 31}

These three lengths can form a triangle, an isosceles triangle.

Isosceles triangles have three different side lengths.

Hope this helps you. Best of Luck!

5 0
3 years ago
1,985 + 12,000 + what ? = 14,471 .
Scrat [10]

Answer:

486

Step-by-step explanation:

1,985 + 12,000 + x = 14,471

x = 14471 - 12000 - 1985

x = 486

6 0
3 years ago
Read 2 more answers
Roma sherry drove 80 miles from her home town to her​ parents' town. during her return​ trip, she was able to increase her speed
mr_godi [17]
<span>Answer: Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home. : Let s = original speed then (s+11) = return speed : Write a time equation: Time = distance%2Fspeed : Original time = return time + 1 hr 330%2Fs = 330%2F%28%28s%2B11%29%29 + 1 : Multiply equation by s(s+11) and you have: 330(s+11) = 330s + s(s+11) : 330s + 3630 = 330s + s^2 + 11s : 0 = 330s - 330s + s^2 + 11s - 3630 : A quadratic equation: s^2 + 11s - 3630 = 0 Factor this to: (s + 66)(s - 55) = 0 Positive solution s = 55 mph is original speed. : Find the time 330/55 = 6 hr, original time and 330/66 = 5 hrs, faster time; confirms our solution.</span>
7 0
3 years ago
A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr
Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at 27 mi/hr in for two hours. Therefore, the side a is:

a=(27 mi/hr)(2 hr)=54mi

- The second ship travels at 18 mi/hr for 1.5 hours. Therefore, the side b is:

b=(18mi/hr)(1.5hr)=27mi

- Now, you can calculate c:

c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi

The answer is: 44 miles

8 0
2 years ago
What one was c because all them look alike but different solutions
ElenaW [278]
I don't know what c you are talking about because there is no picture
4 0
3 years ago
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