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professor190 [17]
3 years ago
6

Limit as x approaches 0 of csc3x/cotx

Mathematics
1 answer:
jolli1 [7]3 years ago
6 0
Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.

For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3

We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3

So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3

<span>\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}</span>

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1 year ago
If the probability density of a random variable is given by find the probabilities that a random variable having this probabilit
kolezko [41]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

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3 0
4 years ago
Write:<br> 3^-4 in standard form
pav-90 [236]

Answer:

\frac{1}{81}

Step-by-step explanation:

<u>Key skills: Exponents + Fractions</u>

Use the negative exponent property. If your number is x^-y then it would be the same as 1/x^y

3^-4 is the same as \frac{1}{3^{4}}

3^4 is 81, so your answer would be 1/81.

Hope you have a nice day and understood this!

4 0
3 years ago
Simplify 24/60 answer this plz
solniwko [45]
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8 0
3 years ago
Which of the points listed below is not on the line with equation 7y+2=3x-5
kicyunya [14]

Answer: Second option.

Step-by-step explanation:

Given the folllowing Linear Equation:

7y+2=3x-5

You need to substitute the coordinates of each point given in the options into the equation and then evaluate.

1) Substituting  (2, -\frac{1}{7}) into the equation, you get:

7(-\frac{1}{7})+2=3(2)-5\\\\-1+2=6-5\\\\1=1\ (TRUE)

2) Substituting the point (3, -\frac{3}{7}). you get:

7(-\frac{3}{7})+2=3(3)-5\\\\-3+2=9-5\\\\-1=4\ (FALSE)

3) Apply the same procedure using the point (1, -\frac{4}{7}):

 7(-\frac{4}{7})+2=3(1)-5\\\\-4+2=3-5\\\\-2=-2\ (TRUE)

4)  Apply the same procedure using the point (-1, -\frac{10}{7})

 7(-\frac{10}{7})+2=3(-1)-5\\\\-10+2=-3-5\\\\-8=-8\ (TRUE)

5) Substituting  (0,-1) into the equation:

 7(-1)+2=3(0)-5\\\\-7+2=-0-5\\\\-5=-5\ (TRUE)

Therefore, the point (3, -\frac{3}{7})  is not on the given line.

8 0
3 years ago
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