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professor190 [17]
3 years ago
6

Limit as x approaches 0 of csc3x/cotx

Mathematics
1 answer:
jolli1 [7]3 years ago
6 0
Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.

For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3

We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3

So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3

<span>\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}</span>

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Using the formula C=2pi r find the circumference of a circle with diameter of 28 inches. Round your answer to the nearest inch.
Ivenika [448]

Answer: 88 inches

Step-by-step explanation:

We know that the formula to find the circumference of circle is given by :-

C=2\pi r, where r is the radius of the circle.

Given : Diameter of circle = 28 inches

Also, diameter is twice of radius.

i.e. 2r=28

Therefore, the circumference of circle will be :-

C=2\pi r=(2r)\pi=28\times(3.14)=87.92text{ inches}\approx88\text{ inches}

Hence, the  circumference of circle is 88 inches.

5 0
3 years ago
What's 19/30 x 12/16?
mr Goodwill [35]
19/40 as a fraction and decimal it is 0.475
6 0
3 years ago
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Mr. Arnold drives 130 miles round trip to work 5 days a week. Write and solve an equation to find how many miles he drives in 60
mart [117]

Answer:

The answer is D.

Step-by-step explanation:

130 x 60 = 7,800 miles.  you don't need the extra information "5 days a week" to solve the problem.  

3 0
3 years ago
Help please thanks so much
suter [353]

Answer:

4/6 0r 2/3

Step-by-step explanation:

5 0
3 years ago
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Solve the following initial-value problem:<br><br> (ex+y)dx+(3+x+yey)dy=0, y(0)=1<br><br> 0=
alex41 [277]

Answer:

e^x+xy+3y+(y-1)e^y=4

Step-by-step explanation:

Given that

(e^x+y)dx+(3+x+ye^y)dy=0

Here

M=e^x+y

N=3+x+ye^y

We know that

M dx + N dy=0 will be exact if

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}

So

\frac{\partial M}{\partial y}=1

\frac{\partial N}{\partial x}=1

it means that this is a exact equation.

\int d\left(e^x+xy+3y+(y-1)e^y\right)=0

Noe by integrating above equation

e^x+xy+3y+(y-1)e^y=C

Given that

x= 0 then y= 1

e^0+0+3+(1-1)e^1=C

C=4

So the our final equation will be

e^x+xy+3y+(y-1)e^y=4

3 0
3 years ago
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