Which of the following is not a possible answer to a probability question?
1 answer:
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We are given these three people age below:
- Jim's age
- Carla's age
- Tomy's age
We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.
- Jim's age = x
Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.
- Carla's age = x+5
Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).
- Tomy's age = 6+(x+5)
The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.
Combine like terms and solve for x.
Then we substitute the value of x in ages to find these three people ages.
- Jim's age = x = 5
- Carla's age = x+5 = 5+5 = 10
- Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.
Answer
- Jim's age = 5
- Carla's age = 10
- Tomy's age = 16
Answer:
0.1505 = 15.05% probability that the hockey team wins 6 games in November
Step-by-step explanation:
For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that a certain hockey team will win any given game is 0.3723
So
12 games in November
So
What is the probability that the hockey team wins 6 games in November?
This is
0.1505 = 15.05% probability that the hockey team wins 6 games in November