Answer:
x=3, y=1
Step-by-step explanation:
2x+y =7
3x-4y =5
Multiply the first equation by 4 so we can eliminate y
4(2x+y =7)
8x +4y =28
Add this to the second equation
8x +4y =28
3x-4y =5
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11x = 33
Divide by 11
11x/11=33/11
x=3
Now we still need to find y
2x+y=7
2(3)+y =7
6+y=7
Subtract 6 from each side
6-6+y=7-6
y= 1
Answer:$75.04
Step-by-step explanation:
last year price=$67
12% of 67
12/100 x 67
(12 x 67) ➗ 100
804 ➗ 100=8.04
Since it has risen by 12%
There new price is 67+8.04=75.04
The answer is c because you have to say 27 minus the number minus 3
1) Change radical forms to fractional exponents using the rule:The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>
![\sqrt[n]{3} = 3^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B3%7D%20%3D%20%20%203%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D)
.
The square root of 3 (

) = 3 to the one-half power (

).
The 5th root of 3 (
![\sqrt[5]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3%7D%20)
) = 3 to the one-fifth power (

).
2) Now use the product of powers exponent rule to simplify:This rule says

. When two expressions with the same base (a, in this example) are multiplied, you
can add their exponents while keeping the same base.
You now have

. These two expressions have the same base, 3. That means you can add their exponents:
3) You can leave it in the form
or change it back into a radical ![\sqrt[10]{3^7}](https://tex.z-dn.net/?f=%20%5Csqrt%5B10%5D%7B3%5E7%7D%20)
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Answer:
or