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Nezavi [6.7K]
3 years ago
13

1) Find the 128th term for the sequence 9, 4, -1, -6, 11,...

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0
To determine an nth term of an arithmetic sequence, we use the expression an = a1 + (n-1)d where a1 is the first term in the sequence, n is the number of the term in the sequence and d is the common difference. For a geometric sequence, it is expressed an = a1r^(n-1). We calculate as follows:

1. a128 = 9 + (128-1)(-5)
     a128 = -626

2. a97 = (-3)(-2)^(97-1)
    a97 = -2.377x10^29
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(04.04 MC)
sp2606 [1]

Answer:

y = x^2/ 60 + 15

=>( x - h)^2 = 4a[ (x^2/6 + 15) - k ].

Step-by-step explanation:

Okay, in order to solve this question very well, one thing we must keep at the back of our mind is that the representation for the equation of a parabola is given as ; y = ax^2 + bx + c.

That is to say; y = ax^2 + bx + c is the equation for a parabola. So, we should be expecting our answer to be in this form.

So, from the question above we are given that "the satellite dish will be in the shape of a parabola and will be positioned above the ground such that its focus is 30 ft above the ground"

We will make an assumption that the point on the ground is (0,0) and the focus is (0,30). Thus, the vertex (h,k) = (0,15).

The equation that best describes the equation of the satellite is given as;

(x - h)^2 = 4a( y - k). ------------------------(1).

[Note that if (h,k) = (0,15), then, a = 15].

Hence, (x - 0)^2 = (4 × 15) (y - 15).

x^2 = 60(y - 15).

x^2 = 60y - 900.

60y = x^2 + 900.

y = x^2/ 60 + 15.

Hence, we will have;

(x - h)^2 = 4a[ (x^2/6 + 15) - k ].

5 0
3 years ago
What is a non example of a rate?
Temka [501]
A rate is common. 

Lets find something that isn't constant. 

The speed a runner can't be constant

Perhaps they run for 1 hour and get 1 mile done, and the other hour, they run 1.3 miles in 1 hour. 
6 0
3 years ago
The purpose of solving equations is to solve application problems.<br> True or False
Vanyuwa [196]

The answer is true, we study mathematics and the properties of numbers, and we learn to solve equations for one major purpose: to solve practical application problems.

5 0
3 years ago
Read 2 more answers
Please solve x. Then, circle whether each angle pair is complementary or supplementary​
marishachu [46]

90-72=18

3x-3=18

3x=15

×=5

8 0
3 years ago
A family has annual loan payments equal to 30% of their annual income. During the year, their loan payments total $15,680. What
soldier1979 [14.2K]
 First, set up a ratio: \frac{30}{100} =  \frac{15,680}{x}
The first fraction is the percentage (30% and \frac{30}{100} are the same thing) and the second is the loan payment (which is equal to the 30 in the first fraction) over their annual income (x).
 First you divide $15,680 by 30, then multiply that quantity by 100. The value calculated then replaces x in your second fraction: \frac{30}{100} =  \frac{15,680}{52,266.67}
7 0
3 years ago
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