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3 years ago

1) Find the 128th term for the sequence 9, 4, -1, -6, 11,...

1 answer:

5 0

To determine an nth term of an arithmetic sequence, we use the expression an = a1 + (n-1)d where a1 is the first term in the sequence, n is the number of the term in the sequence and d is the common difference. For a geometric sequence, it is expressed an = a1r^(n-1). We calculate as follows:

1. a128 = 9 + (128-1)(-5)
a128 = -626

2. a97 = (-3)(-2)^(97-1)
a97 = -2.377x10^29

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What additional information can be used to prove ΔDSB ≅ ΔTSR by SAS?

Elden [556K]

Please find the attached file for a proper understanding of the question given here. The diagram in the file attached is the complete accompanying diagram of the question.

As per that diagram, $RS\cong SB$ (which is given)

and we know that $\angle DSB\cong \angle RST$ (vertically opposite angles).

Thus, the only way ΔDSB ≅ ΔTSR by SAS is when $DS\cong ST$ as indicated in the diagram.

Thus, $DS\cong ST$ is the correct answer.

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3 years ago

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Find the equation of the line that passes through the point (-2,7) and is perpendicular to the line y= 2/5x-1/5

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Step-by-step explanation:

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2 years ago

Y = x^3 + 5x^2 + 3x x= -3

dexar [7]

Answer:

Step-by-step explanation:

-3^3 +5*(3)^2 +3*-3

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2 years ago

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This graph has rotational symmetry about the points

mart [117]

Answer: Answer for figure one is origin (0,0)

Answer for figure two is (2,4) /

Step-by-step explanation:

a) Here we can see that given graph is the equation of cubic function which is

f(-x) = -f(x) that is given function is odd then rotational symmetry point is origin always ,therefore point of rotational symmetry is origin (0,0)

b) The rotational symmetry of an ellipse is 180 degrees about the center of the ellipse .

And here the center of given ellipse is (2,4) ,therefore its rotational symmetry is about (2,4) That is if we rotate the given ellipse 180 degrees about (2,4) it will be at its original position.

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2 years ago

What is the vertex of the graph of y = x2 + 4x? (–2, –12) (–2, –8) (–2, –6) (–2, –4)

SCORPION-xisa [38]

Answer: The vertex of the parabola (quadratic function) is (-2,-4)

Fourth option: (-2,-4)

Solution:

y=x^2+4x

y=ax^2+bx+c; a=1, b=4, c=0

Vertex: V=(h,k)

h=-b/(2a)

h=-4/(2(1))

h=-4/2

h=-2

y=x^2+4x

k=y=h^2+4h

k=(-2)^2+4(-2)

k=4-8

k=-4

Vertex: V=(h,k)

Vertex: V=( -2, -4)

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3 years ago

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