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3 years ago

1) Find the 128th term for the sequence 9, 4, -1, -6, 11,...

1 answer:

5 0

To determine an nth term of an arithmetic sequence, we use the expression an = a1 + (n-1)d where a1 is the first term in the sequence, n is the number of the term in the sequence and d is the common difference. For a geometric sequence, it is expressed an = a1r^(n-1). We calculate as follows:

1. a128 = 9 + (128-1)(-5)
a128 = -626

2. a97 = (-3)(-2)^(97-1)
a97 = -2.377x10^29

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Given A= <br> What is the value of matrix B if A + B = C

tangare [24]

Answer:

Step-by-step explanation:

We know that 8+3x= x

solve for x

8= -2x

-4 =x

The only answer that has -4 is A

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3 years ago

The sum of scores of ella and Kath in the summative test is not greater than 50. supposed Ella's score is 22 points, what could

Firlakuza [10]

We want to see which could be the possible score of Kath for the given information. We will find the inequality:

K ≤ 33

<h3>Stating what we know:</h3>

The given information is:

The sum of the scores is not greater than 55 points
Ella's score is 22 points.

<h3>Writing the inequality:</h3>

First, we need to define the variable K for Kath's points, because of the given information, we can write the inequality:

K + 22 ≤ 55

This means that the sum of the points is smaller than or equal to 55.

Now we just need to solve this for K, to do this, we subtract 22 in both sides:

K ≤ 55 - 22

K ≤ 33

From this, we can conclude that Kath has at most 33 points.

If you want to learn more about inequalities, you can read:

brainly.com/question/11234618

7 0

2 years ago

12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is $6 a b^{2}(a+2)(2 a-1)$

<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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3 years ago

The radius of the base of a right circular cone is 4 in., and its slant height is 15 in. If the radius and the slant height are

alukav5142 [94]

Answer:

Step-by-step explanation:

radius r = 4 in

slant height L = 15 in

base area = πr² = 16π in²

lateral area = πrL = 60π in²

surface area = 76π in²

r = 4×6, L = 15×6

base area = (4×6)²π = 16π×36

lateral area = 60π×36

surface area is multiplied by 36

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3 years ago

Fourtine equals a divided by two

lions [1.4K]

Answer:

a=28

Step-by-step explanation:

use inverse operations

5 0

3 years ago