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Zina [86]
2 years ago
14

Work out the number of ham sandwiches Tina had

Mathematics
1 answer:
arlik [135]2 years ago
4 0

Answer:

Number of ham sandwiches Tina made = 60

Step-by-step explanation:

Total number of sandwiches = 480

Fraction of total sandwiches which are Tuna = \frac{3}{8}

Therefore, number of Tuna sandwiches = 480\times \frac{3}{8}

                                                                   = 180

Percentage of beef sandwiches = 35%

Therefore, beef sandwiches = 480\times \frac{35}{100}

                                                = 168

Ratio of ham sandwiches (h) and cheese sandwiches (c) = 5 : 6

\frac{h}{c}=\frac{5}{6}

c=\frac{6}{5}h ------(1)

Total number of Tuna sandwiches + Total number of beef sandwiches + Total number of ham sandwiches + Total number of cheese sandwiches = 480

180 + 168 + h + c = 480

h + c = 480 - 348

h + c = 132

Substitute the value of c from equation (1),

h+\frac{6}{5}h=132

\frac{11}{5}h=132

h=\frac{132\times 5}{11}

h=60

Therefore, number of ham sandwiches Tina made = 60

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<span> -8x=72-16y             
4x=-92+16y        <= Mult. all 3 terms by 2:          8x = - 184 + 32y

Now combine the following, column by column:

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   0 = -112 + 16y.  Solving for y, 16y = 112, and y = 7.

Now subst. 7 for y in either of the original equations and calculate x:

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A population of monkeys' tail lengths is normally distributed with a mean of 25 cm with a standard deviation of 8 cm. I am prepa
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Answer:

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = 0.4772</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

<em>Given mean of the Population  'μ'= 25c.m</em>

<em>Given standard deviation of the Population 'σ' = 8c.m</em>

<em>Given sample size 'n' = 256</em>

<em>Let X₁ = 24</em>

<em></em>Z_{1}  = \frac{x_{1}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{24-25}{\frac{8}{\sqrt{256} } } =  -2<em></em>

<em>Let X₂ = 25</em>

<em></em>Z_{2}  = \frac{x_{2}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{25-25}{\frac{8}{\sqrt{256} } } = 0<em></em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = P(-2≤ Z ≤0)</em>

                     = P( Z≤0) - P(Z≤-2)

                     = 0.5 + A(0) - (0.5- A(-2))

                     = A(0) + A(2)        ( ∵A(-2) =A(2)

                     = 0.000+ 0.4772

                     = 0.4772

<u><em>Final answer</em></u>:-

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = 0.4772</em>

                     

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