hi
1st draw: green
2/12. (2 green out of 12 marbles), reduces to 1/6
2nd draw: blue
4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)
Probability of theses BOTH happening: multiply these individual probabilities.
Conditional probability:
P(a and b) = P(a)P(b|a)
Prob(event 1) × Prob(event 2 given event 1).
1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.
0.2, 0.75, 60%, 1/2, 1, 1 1/4
60% is the same as 60/100 or 0.6
1 1/4 is the same as 5/4 or 1.25
1/2 is the same as 0.5
Now our list is
0.2, 0.75, 0.6, 0.5, 1.25 and 1
So from largest to smallest your answer would be...
1.25 , 1 , 0.75 , 0.6 , 0.5 , 0.2
B. 2
4x + 3 = 7x - 3
7x - 4x = 3 + 3
3x = 6
x = 2
The answer is 8 because:
24 divided by 3 = y and y is 8
1/3*(24^2)*30=5760
Any questions just ask. Thanks
