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BartSMP [9]
3 years ago
8

NEED HELP ASAP, WILL GIVE BRAINLIEST

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

The answer is C. 35, 7

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One way to determine if a given point is on the graph of a linear equation is by checking to see if it is a solution to the equa
nexus9112 [7]

Find the slope or the y-intercept.

4 0
3 years ago
In ΔVWX, the measure of ∠X=90°, XW = 20, WV = 29, and VX = 21. What ratio represents the cosine of ∠W?
zhuklara [117]
20/29

That would be the answer
4 0
2 years ago
The dimensions of a right rectangular prism are shown below. 1 in. 1a in. 2 in. in. How many cubes with side lengths of inch are
Dafna1 [17]

First we neeed to find the volume of the rectangular prism

V=\text{ l}\times w\times hV=1\times1\frac{1}{6}\times2\frac{1}{6}=1\times\frac{7}{6}\times\frac{13}{6}=\frac{91}{36}in^3

Volume of cube with side lengths 1/6 = 1/6 x 1/6 x 1/6 = 1/216

The number of cubes needed to fill the prism without gaps or overlaps =

=\frac{91}{36}\text{  divide by }\frac{1}{216}=\frac{91}{36}\times\frac{216}{1}=\frac{19656}{36}=546

3 0
1 year ago
Order each set of numbers from least to greatest.<br><br><br> PLZ HELP ASAP
Wittaler [7]

Answer:

<h3><u>7. Ans ;</u></h3>

\frac{41}{3}  < 14 <  \sqrt{200}

<h3><u>8</u><u>.</u><u> </u><u>Ans</u><u> </u><u>;</u></h3>

<u>0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }</u>

Step-by-step explanation:

<h3><u>7. Ans ;</u></h3>

\sqrt{200}  = 10 \sqrt{2}  = 14.1 \\ 14 = 14 \\  \frac{41}{3}  = 13.6

So ;

\frac{41}{3}  < 14 <  \sqrt{200}  \\ 13.6 < 14 < 14.1

<h3><u>8. Ans ;</u></h3>

\frac{2}{3}  = 0.66 \\  \sqrt{ \frac{9}{16} }   =   \frac{3}{4}  = 0.75 \\ 0.6 = 0.6

So ;

0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }  \\ 0.6 < 0.66 < 0.75

I hope I helped you^_^

6 0
2 years ago
Find the value of x. Then find the measure of each labeled angle.<br> (4x + 12)<br> (In picture)
Lelechka [254]

Answer:

(4x+12)=90

x= 19.5

Step-by-step explanation:

3 0
3 years ago
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