Question

If the sum of three consecutive numbers is 36. Find the numbers.

Answer 1

Answer:

11, 12, 13

Step-by-step explanation:

x is the first number

(x + 1) is the second number

(x + 2) is the third number

x + x+1 + x+2 = 36

3x + 3 = 36

3x = 36 - 3

3x = 33

x = 11  ← the first number

the second number  = x + 1 = 11 + 1 = 12

the third number = x + 2 = 11 + 2 = 13

Answer 2

$\huge{\boxed{11}}\ \ \huge{\boxed{12}}\ \ \huge{\boxed{13}}$

First, represent the numbers with variables. $x$ is the first number. $x+1$ is the second number, since they are consecutive. $x+2$ is the third and final number.

Make a statement. $x+x+1+x+2=36$

Combine the variables. $3x+1+2=36$

Combine the constants. $3x+3=36$

Isolate the variable by subtracting $3$ on each side. $3x=33$

Finish isolating the variable by dividing both sides by $3$. $x=11$

This means the first number is $\boxed{11}$. Since the three numbers are consecutive, the other two numbers are $\boxed{12}$ and $\boxed{13}$.

We can then check out work by adding these three numbers together. If they equal $36$, then the answer is correct. $11+12+13=36$

Add $11$ and $12$. $23+13=36$

Add $23$ and $13$. $36=36$

This means our answer is correct.