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Answer:
∠CAB = 28°
∠DAC = 64°
Step-by-step explanation:
What you do in each case is make use of the relationships you know about angles in a triangle and around parallel lines. You can also use the relationships you know about diagonals in a rectangle, and the triangles they create.
<u>Left</u>
Take advantage of the fact that ∆AEB is isosceles, so the angles at A and B in that triangle are the same. If we call that angle measure x, then we have the sum of angles in that triangle is ...
x + x + ∠AEB = 180°
2x = 180° -124° = 56°
x = 28°
The measure of angle CAB is 28°.
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<u>Right</u>
Sides AD and BC are parallel, so diagonal AC can be considered a transversal. The two angles we're concerned with are alternate interior angles, so are congruent.
∠BCA = ∠DAC = 64°
The measure of angle DAC is 64°.
(Another way to look at this is that triangles BCE and DAE are congruent isosceles triangles, so corresponding angles are congruent.)
Answer:
-2
Step-by-step explanation:
I actually just did functions in math at the end of last semester I offer you my condolences dude
No, the ratios aren’t equivalent
Answer:
x=20
Step-by-step explanation:
Hello There!
Remember the exterior angle of a triangle rule:
An exterior angle of a triangle is equal to the sum of the opposite interior angles
Knowing this, we can create an equation to solve for x
exterior angle (100) = sum of opposite interior angles (3x+2x)
100 = 2x+3x
now we solve for x
step 1 combine like terms
2x+3x=5x
now we have 100=5x
step 2 divide each side by 5
5x/5=x
100/5=20
we're left with x = 20
