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3 years ago

Which expression is not equal to 1?

Mathematics

2 answers:

liq [111]3 years ago

5 0

Hopes this helps if it is wrong I am so sorry:

Answer: sin 0 cos 0

Dafna1 [17]3 years ago

5 0

sin θ cos C

Step-by-step explanation:

Suppose, θ=30°

Suppose,

sin θ cos θ=1

⇒sin30°cos30°=1

⇒ $\frac{1}{2}$ × $\frac{\sqrt{3\\} }{2}$ =1

⇒ $\frac{\sqrt{3} }{4}$ ≠1

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If you use photomath itll help you

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4 years ago

The scale on a map shows that 1 cm equals 10km if the distance between 2 cities on the map is 4.5 cm how far is the actual dista

ikadub [295]

Answer:

45 km

Step-by-step explanation:

Let's review the scale factor of this problem.

1 cm = 10 km

This means that for every 1 cm of distance on the map, 10 km is represented in the real world. Because of this, we know that dividing the actual distance by 10 will give us the distance on the map.

Ex. 40 km in real world = 4 cm on map

So, we will use d to represent the actual distance.

d=distance in real world

Then, we will divide d by 10 and set it equal to 4.5, because that's the distance on the map.

d/10 = 4.5

Now to solve this equation, we just have to multiply both sides by 10.

d=45

This is your answer.

4 0

3 years ago

How many 3/4 cup servings are in 12 cups of cherries?

AveGali [126]

Answer:

16 serving.

Step-by-step explanation:

Given: 3/4 cup servings.

Now, computing the number of serving in 12 cups of cherries.

Using unitary method to solve.

∴ Number of serving= $total\ cups \times number\ of\ serving\ per\ cup$

Number of serving in one cup is $\frac{4}{3}$

Number of serving in 12 cups = $12\times \frac{4}{3} = 16 \ serving$

Number of serving in 12 cups= $16\ serving$

∴ There are 16 serving is possible in 12 cups of cherries.

8 0

3 years ago

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$