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3 years ago

Same with the previous questionGrammer Topic ADJECTIVES

Advanced Placement (AP)

1 answer:

Luba_88 [7]3 years ago

7 0

Explanation:

1 cute

2 very

3 meet

4 was

5 should

6 some

7 there

8 first

9 third

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Diesel exhaust fluid is injected A. after the oxidation catalyst. B. at the end of the tail pipe. C. into the exhaust manifold.

san4es73 [151]

Answer - C

Diesel exhaust fluid (DEF; an aqueous urea solution) is injected into the exhaust manifold (upstream of a catalyst) at a precise dosing rate. In the exhaust pipeline, the aqueous urea vaporizes and decomposes to form ammonia (which is the desired product) and carbon dioxide.

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3 years ago

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Can someonetell me something new they learn today.

Paha777 [63]

Answer:

That an African American man is the founder of BET

Explanation:

My Teacher

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Explain in detail, how you solved the following problem: The first two terms of a sequence are 10 and 20. If each term after the

KIM [24]

Answer:

$T_{2020} = 15$

Explanation:

Given

$T_1 = 10$

$T_2 = 20$

Each term after the second term is the average of all of the preceding terms

Required:

Explain how to solve the 2020th term

Solve the 2020th term

Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.

The very first thing to do is to solve for the third term;

The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term

This is proved as follows;

From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

$T_{n} = \frac{\sum T{k}}{n-1} ; where: k = 1 .... n -1$

Assume n = 3

$T_{3} = \frac{T_1 + T_2}{2}$

Multiply both sides by 2

$2 * T_{3} = \frac{T_1 + T_2}{2} * 2$

$2T_{3} = T_1 + T_2$

Assume n = 4

$T_{4} = \frac{T_1 + T_2 + T_3}{3}$

$T_{4} = \frac{(T_1 + T_2) + T_3}{3}$

Substitute $2T_{3} = T_1 + T_2$

$T_{4} = \frac{2T_3 + T_3}{3}$

$T_{4} = \frac{3T_3}{3}$

$T_{4} = T_3$

Assume n = 5

$T_{5} = \frac{T_1 + T_2 + T_3 +T_4}{4}$

$T_{5} = \frac{(T_1 + T_2) + T_3 +(T_4)}{4}$

Substitute $2T_{3} = T_1 + T_2$ and $T_{4} = T_3$

$T_{5} = \frac{2T_3 + T_3 +T_3}{4}$

$T_{5} = \frac{4T_3}{4}$

$T_{5} = \frac{(5-1)T_3}{5-1}$

Replace 5 with n

$T_{n} = \frac{(n-1)T_3}{n-1}$

(n-1) will definitely cancel out (n-1); So, we're left with

$T_{n} = T_3$

Hence,

$T_{2020} = T_3$

Calculating $T_3$

$T_{3} = \frac{10 + 20}{2}$

$T_{3} = \frac{30}{2}$

$T_{3} = 15$

Recall that $T_{2020} = T_3$

$T_{2020} = 15$

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3 years ago

5. Of the following gases which is the least abundant gas in our atmosphere?

dimaraw [331]

The least abundant gas in out atmosphere is Carbon dioxide at 0.03%.

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3 years ago

What happens when you multiply 4 times 2, add 6, divide by 2, subtract 3 explain

dezoksy [38]

4•2+6/2-3=4

The answer would be 4
Because four times two is eight
Then eight plus six is fourteen
Then fourteen divided by two is seven
Then seven minus four is four

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3 years ago

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Same with the previous questionGrammer Topic ADJECTIVES​

Same with the previous questionGrammer Topic ADJECTIVES