Using the digits 1-9 once only fill in the blanks so that you can multiply each column and row to get the answer given on the si
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2 answers:
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The problem is modelled in the first picture shown below
To work out the resultant vector, we modelled the vectors 150N and 75N as triangle AOB is shown in the second picture with AB as the resultant vector.
We use the cosine rule to work out the length AB
(nearest whole number)
The third picture shows the full diagram of the vectors
To work out the direction of the resultant vector, we use the sin rule to find the size of angle A and angle B
Angle A
(rounded to nearest whole number)
Angle B
Direction is 60° toward negative x-axis
Answer: Magnitude 130N and direction 60° toward negative x-axis
To work out the resultant vector, we modelled the vectors 150N and 75N as triangle AOB is shown in the second picture with AB as the resultant vector.
We use the cosine rule to work out the length AB
The third picture shows the full diagram of the vectors
To work out the direction of the resultant vector, we use the sin rule to find the size of angle A and angle B
Angle A
Angle B
Direction is 60° toward negative x-axis
Answer: Magnitude 130N and direction 60° toward negative x-axis
You are essentially asking at this point where is the quadratic function greater than 0. To get the interval find the roots. Between the roots the function is guaranteed to be LESS THAN zero. Everywhere else the function is greater than 0.
Use Vieta's rule to get the roots,
Both roots are the same so no value is less than 0 which means all values except at the point of root are strictly greater, the point of root is at which means the set for which the quadratic function is greater than 0 is
"all real numbers except 1".
To convert this into interval notation use all numbers up to 1 but not including and all numbers after 1 but not including,
Hope this helps :)