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Tasya [4]
2 years ago
6

Ben is repackaging a 45 pound bag of rice into 6 smaller bags. How much rice is going to be in each bag

Mathematics
1 answer:
irina1246 [14]2 years ago
7 0
Answer. 7.5 pounds in each bag

Explanation Divide 45 by 6
You might be interested in
How many more puppies weighed 3 pounds than 7 pounds
lara [203]

Answer:

It might be 4 pounds?

Step-by-step explanation:

7-3= 4

but this might be wrong

6 0
2 years ago
MUSIC A song has 28 beats in 4 seconds. At this rate, how many beats are there in 30 seconds?
Deffense [45]
In 4 seconds, number of beats = 28
In 1 sec., it is = 28/4 = 7

Now, In 30 seconds, it would be: 30 * 7 = 210

In short, Your Answer would be: 210 beats

Hope this helps!
4 0
3 years ago
Read 2 more answers
You spin the spinner, flip a coin, and spin the spinner again. What is the probability you spin an odd, flip tails, and spin a n
ss7ja [257]

Answer:

0 cause u cant spin a number larger than 9.

Step-by-step explanation:

4 0
3 years ago
The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s
Molodets [167]

Answer:

  500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

  f(x,y)=4x+2y\\g(x,y)=2x^2+y-4

The Lagrangian is ...

  \mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2

  \dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5

Since x and y are in thousands, maximum profit is to be had when the company produces ...

  500 Type A souvenirs, and 3500 Type B souvenirs

3 0
3 years ago
Find the least common multiple of these two expressions.<br> 10v^6y^7 and 6w^4v^5y^3
egoroff_w [7]

10v⁶y⁷    = <u>2</u> * 5 * <u>vvvvv</u>v * <u>yyy</u>yyyy      

6w⁴v⁵y³ = <u>2</u> * 3 * wwww * <u>vvvvv</u> * <u>yyy</u>

GCF: 2v⁴y³

<em>The LCM is the GCF and everything leftover</em>

LCM: 2v⁴y³ * (5 * v * yyyy) * (3 * wwww)

       = (2 * 5 * 3) * (v⁴ * v) * (w⁴) * (y³ * y⁴)

       =        30           v⁵        w⁴        y⁷

Answer: LCM =  30v⁵w⁴y⁷

4 0
3 years ago
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