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alexgriva [62]
3 years ago
5

Simplify: (3x^3+2x-3)-(4x^3-x^2+x

Mathematics
2 answers:
adell [148]3 years ago
7 0

Answer:

-x^{3}+x^{2} +x-3

Step-by-step explanation:

Remove Parentheses

Subtract  3x^3-4x^3

Leave x^2

Subtract 2x-x

Leave the 3

<h2><em>:)Hope this Helped You:)</em></h2>
ad-work [718]3 years ago
3 0

Answer: -x^3 - x^2 + 3x - 3

Glad I could help :D

Step-by-step explanation:

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ANSWER FAST ITS URGENT
Vlad1618 [11]

Answer:

9) 6.3 units

11) n=6√2 and m=12,

10) m=6√3, n=6

12) 330.6 ft

Step-by-step explanation:

1) The Pythagoras Theorem says that, the square of the hypotenuse is the sum of the squares of the two shorter legs.

Let the missing side, which is the hypotenuse be x.

Then

{x}^{2}  =  {2}^{2}  +  {6}^{2}

{x}^{2}  = 4 + 36

{x}^{2}  = 40

x =  \sqrt{40}

x = 6.3

The missing side is 6.3 units to the nearest tenth.

2) This is an isosceles right triangle.

This implies that, the two legs are equal.

n = 6 \sqrt{2}

The hypotenuse can be found using Pythagoras Theorem.

{m}^{2}  =  {(6 \sqrt{2} )}^{2}  +  {(6 \sqrt{2} )}^{2}

{m}^{2}  = 36(4)

m =  \sqrt{36 \times 4}  = 6 \times 2 = 12

3) The side lengths of 30°-60°-90° are in the ratio, 2x,x√3,x

From the diagram, the hypotenuse is 12, therefore the other two legs are

n =  \frac{1}{2} (12) = 6

and

m = 6 \sqrt{3}

4) The height of the monument is 115 feet, the hypotenuse is 350.

By Pythagoras Theorem,

{x}^{2}  +  {115}^{2}  =  {350}^{2}

{x}^{2}  =  {350}^{2}   -  {115}^{2}

{x}^{2}  = 109275

x =  \sqrt{109275}  = 330.6 ft

3 0
3 years ago
Given △RST≅△LMN, m∠R=65°, and m∠M=70°, what is the measure of ∠T?
sergey [27]
<T = 45°

Hope this helps!! :)
5 0
3 years ago
Read 2 more answers
The answer because I don’t knkw
Veseljchak [2.6K]

wssss

Step-by-step explanation:

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3 0
3 years ago
how would you arrange four 3's so they equal the number 0 through 10? I did 0 and 1 need help with the other numbers PLEASES!!!
Harlamova29_29 [7]
3+3+3-3=6

(3+3+3-3)÷2=3

(3+3+3+3)÷3=4

(3+3+3+3)÷6=2

Is this how it works?
5 0
3 years ago
Let g(x)= -3x and h(x) x^2+3 Find (g°h)(0)
raketka [301]
<h3>Answer is   -9</h3>

=================================

Work Shown:

(g°h)(x) is the same as g(h(x))

So, (g°h)(0) = g(h(0))

Effectively h(x) is the input to g(x). Let's first find h(0)

h(x) = x^2+3

h(0) = 0^2+3

h(0) = 3

So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.

Now let's find g(3)

g(x) = -3x

g(3) = -3*3

g(3) = -9

-------

alternatively, you can plug h(x) algebraically into the g(x) function

g(x) = -3x

g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)

g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3

g( h(x) ) = -3x^2 - 9

Next we can plug in x = 0

g( h(0) )  = -3(0)^2 - 9

g( h(0) ) = -9

we get the same result.

7 0
3 years ago
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