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Alina [70]
3 years ago
14

A. X=3 m B. X=5 m C. X=6 m D. X=9 m

Mathematics
2 answers:
enyata [817]3 years ago
8 0

Answer:

ok so we can divide 15 by 5 to get 3

so we know the building is 3 times bigger

so we multiply 3 by 3 to get 9

so the answer is D

Ksivusya [100]3 years ago
7 0

Answer:

9

Step-by-step explanation:

Since the triangles are similar, we can use ratios to solve

Letting h be the height of the tower

15        h

-----  = ------

5           3

Using cross products

15*3 = 5h

Divide each side by 5

45/5 = 5h/5

9 = h

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slavikrds [6]

Answer:

The answer for x is ten

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A baker is making cakes for a big party. She uses 1/4 cup of oil for each cake. How many cakes can she make if she has a bottle
Svetradugi [14.3K]

Answer:

24 Cups

Step-by-step explanation:

you just need to divide 6 by 1/4, whihc equals 24/1

3 0
2 years ago
Why is rounding important?
Alik [6]

Answer:

C

Step-by-step explanation:

Rounding can make a long number that might be confusing short and easy to understand. D sounds like the right answer but actually rounding isn't the most accurate. Using a fraction is.

7 0
3 years ago
In the diagram below, PQ and RS are parallel. Based on the angle measures in the diagram, what is the value of X?
Butoxors [25]

Answer:

x would be equal to 70 grades

Step-by-step explanation:

The angle QRS is equal to 180 - 130 = 50 grades.

We add up that with the other 60 grades on the left, and we encounter ourselves with a simple equation:

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Hope this was helpful

4 0
3 years ago
Test for the commutative property of union and intersection of the sets P = { x : x is all real numbers between 2 and 7} and Q =
In-s [12.5K]

Answer:

Step-by-step explanation:

P = {x : x is a real number between 2 and 7}

{x: 3,4,5,6}

Q = {x : x is all rational number between 2 and 7}

{4 }

We know that P contains all the rational numbers between 2 and 7.

And P ∪ Q and Q ∪ P each of them contain all the real numbers which are between 2 and 7.

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Here Q is the proper subset of P

P ∩ Q = Q ∩ P = Q= {4}

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3 years ago
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